Answer:
I think they first one is .5 and I'm not sure on the other
Answer:
Step-by-step explanation:
f(x) = x⁵ – 8x⁴ + 16x³
As x approaches +∞, the highest term, x⁵, approaches +∞.
As x approaches -∞, x⁵ approaches -∞ (a negative number raised to an odd exponent is also negative).
Now let's factor:
f(x) = x³ (x² – 8x + 16)
f(x) = x³ (x – 4)²
f(x) has roots at x=0 and x=4. x=4 is a repeated root (because it's squared), so the graph touches the x-axis but does not cross at x=4.
The graph crosses the x-axis at x=0.
<span>Let's say e=a^2−b^2 and take each affirmation:
a. </span><span>both coefficients are perfect squares.
</span><span>a could be equal to 2 which is not a perfect square
b. </span><span>there are only two terms - obviously yes
</span><span>
c. </span>both terms have negative coefficients - as we can see just b has a negative <span>coefficient
Final answer b. </span><span>there are only two terms.</span>
<span>
</span>
Answer:
Plot the point (3, -5)
Step-by-step explanation:
Recall that the general number a+bi can be plotted on a complex plane with the x axis as the real part and the y axis as the imaginary part.
In short,
a = real part = x
b = imaginary part = y
So (a,b) = (x,y)
In this case, a = 3 and b = -5 which is how I got (3, -5).
It might help to rewrite 3 - 5i into 3 + (-5)i
