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stiks02 [169]
3 years ago
14

1.y-y1=m(x-X1) 2. Find slope between (1,3) and (5,1) Y1-Y2 X1-X2 Y-3 =

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0
Slope= Y2-Y1/X2-X1
1-3/5-1
-2/4
-1/2= slope
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What is 522,000 rounded to the nearest tenth.
tiny-mole [99]
522,000. This is most likely a question meant to trick you.
3 0
2 years ago
Segment BD is an altitude of triangle ABC. Find the area of the triangle.
Sever21 [200]

Answer: The correct option is A, i.e., 7.5.

Explanation:

It is given that ABC is a triangle and BD is an altitude.

Since BD is an altitude, therefore the height of the triangle is BD and the base of the triangle is AC.

The distance formula to find the distance between two points is,

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

First, we find BD, where B(-1,4) and D(2,4).

BD=\sqrt{(2+1)^2+(4-4)^2}=\sqrt{9} =3

So, the height of the triangle is 3.

Now, we find the value of AC, where A(2,1) and C(2,6).

AC=\sqrt{(6-1)^2+(2-2)^2}=\sqrt{25} =5

So, the base of the triangle is 5.

The formula to find the area of a triangle is,

A=\frac{1}{2}\times {\text{base}}\times {\text{height}}

A=\frac{1}{2}\times 5\times 3=\frac{15}{2}=7.5

Therefore, the area of the triangle is 7.5 unit square and the correct option is A.

6 0
3 years ago
Read 2 more answers
If the area of a park is exactly halfway between 2.4 and 2.5 acres what is the area of the park
Paul [167]
Get the distance between two acres.

2.5 - 2.4 = 0.1

Divide the diffence by 2
0.1 / 2 = 0.05 - Halfway between them.

Therefore, 0.05 must be taken from 2.5 acres. it must be added to 2.4 acres to get the exact area of the park.

2.5 - 0.05 = 2.45
2.4 + 0.04 = 2.45 acres

OR

Simply get the average of the two to get the area since it is exactly halfway between the two acres of land.

2.5 + 2.4 = 2.9 / 2 = 2.45 acres
8 0
2 years ago
Read 2 more answers
A line segment of length k is divided into 3 equal parts what is the distance between midpoints of the first and third segments
anastassius [24]

Line segment of length k is divided into 3 equal parts.

so first segment is 0-k/3 and third segment is 2/3k-k

so mid-pt of 1st = k/6 and 3rd = 5/6k

so the distance in between = 5/6k-k/6 = 4/6k = 2/3k

4 0
2 years ago
If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1)<br><br><br>FIRST BEST ANSWER BRAINLIEST
AURORKA [14]

Answer: See below

Step-by-step explanation:

h\:\circ \:g=h\left(g\left(x\right)\right)

=5\left(7x^2-4x-3\right)^2-12\left(7x^2-4x-3\right)

=5\left(7x^2-4x-3\right)\left(7x^2-4x-3\right)-12\left(7x^2-4x-3\right)

=245x^4-280x^3-130x^2+120x+45-84x^2+48x+36

Simplify:

=245x^4-280x^3-214x^2+168x+81

6 0
2 years ago
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