Kiloliters.Hope I helped.
Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
Yeah
Step-by-step explanation:
Well, we can input both variables to check and see if the numbers hold.
-691 = -51(-15) - 74
-691 = 765-64
-691 = 701
(-15, -691) does not make the equation true.
Step-by-step explanation:
p = 0.1, q = 0.9, n = 7
a) Use complementary probability.
P(at least 1) = 1 − P(0)
P(at least 1) = 1 − (0.9)⁷
P(at least 1) = 0.522
b) Use binomial probability.
P = nCr pʳ qⁿ⁻ʳ
P(3) = ₇C₃ (0.1)³ (0.9)⁴
P(3) = 0.023
