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elixir [45]
4 years ago
6

It takes Mark 1 hour to get to work each day. Mark drives from home 20 minutes to the train station at a constant rate of 42 mph

. He then takes the train, traveling at a constant 60 mph, the remaining distance to work. How far does Mark live from his work place? A. 108 mi. B. 80 mi. C. 62 mi. D. 54 mi.
Mathematics
1 answer:
Wewaii [24]4 years ago
5 0

Answer:

B. 80 mi is the answer, pretty confident about it.

Step-by-step explanation:


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Jenna is drawing a sketch of her room. The room is 15 feet long by 12 feet wide. The
SOVA2 [1]

Answer:

4 inches

Step-by-step explanation:

Actual dimensions:

Length = 15 feet

Width = 12 feet

Scale dimensions:

Length = 5 inches

Width = x inches

Write a proportion:

\dfrac{\text{Actual length}}{\text{Scale length}}=\dfrac{\text{Actual width}}{\text{Scale width}}\\ \\ \\\dfrac{15\ feet}{5\ inches}=\dfrac{12\ feet}{x\ inches}\\ \\x=\dfrac{5\ inches\times 12\ feet}{15\ feet}=4\ inches

3 0
4 years ago
7-C=4<br><br><br> Hint: equation and rational coefficient
nalin [4]

Answer:

you stupid and dumb person

5 0
3 years ago
Which weighs the least 2 centigrams 2 grams 2 hectograms 2 kilograms or 2 milligrams
Mekhanik [1.2K]
To answer the question above, use conversion factors and dimensional analysis. In this given, it is easier to use grams as the basis. 

a. (2 centrigrams) x (1 gram / 100 centigrams) = 0.02 grams
b. 2 grams 
c. (2 hectograms) x (1 gram / 0.01 hectogram) = 200 grams
d. (2 kilograms) x (1 gram / 0.001 kilogram) = 2000 grams
e. (2 milligrams) x (1 gram / 1000 millimeters) = 0.002 grams

Thus, the answer is 2 milligrams. 
7 0
3 years ago
M angle PQS= 3x; m angle SQR=5x-20 <br> Find x
Dahasolnce [82]

Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.

Given:

Ray QS bisects ∠PQR.

m∠PQS = 3x

m∠SQR = 5x-20

To find:

The value of x and m∠PQR

Solution:

Ray QS bisects ∠PQR. So,

m\angle PQS=m\angle SQR

3x=5x-20

3x-5x=-20

-2x=-20

x=10

The value of x is 10.

Now,

m\angle PQR=m\angle PQS+m\angle SQR

m\angle PQR=3x+5x-20

m\angle PQR=8x-20

Put x=10,

m\angle PQR=8(10)-20

m\angle PQR=80-20

m\angle PQR=60

Therefore, the m∠PQR is 60 degrees.

5 0
4 years ago
Two similar pyramids have lateral areas 8ft^2 and 18 ft^2. the volume of the large pyramid is 108 ft^2. find the volume of the s
ddd [48]
I assume the volume of the larger pyramid is 108 ft^3, not 108 ft^2.

The scale factor of edges of two solids is x.
The scale factor of their areas is x^2.
The scale factor of their volumes is x^3

The areas have a scale factor of 18/8 = 2.25

The length have a scale factor of sqrt(2.25) = 1.5

The volumes have a scale factor of 3.375

108/3.375 = 32

Answer: 32 ft^3
4 0
3 years ago
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