By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.
<h3>How to determine the distance between two points</h3>
In this problem we must determine the distance between two points that are part of a triangle and we can take advantage of properties of triangles to find it. First, we determine the measure of angle L by the law of the cosine:
L ≈ 62.464°
Then, we get the distance between points M and N by the law of the cosine once again:
MN ≈ 9.8 m
By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.
To learn more on triangles: brainly.com/question/2773823
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Answer:
The first answer: 390m The second answer: x = 7; m<1 = 17; m<2 = 73
Step-by-step explanation:
First problem:
It's asking for the distance he walks by walking around a rectangular box which is the perimeter.
Two of the sides will have length 115m and two will have length 80m. So this perimeter is 115 + 115 + 80 + 80 = 390m.
Second problem:
Complementary angles add to 90 degrees. So m<1 and m<2 added together will equal 90
-4x +45 + 7x + 24 = 90
3x + 69 = 90
3x = 21
x= 7.
Plug back x into both m<1 and m<2 to find the measure of the angles.
m<1 = -4(7) + 45 = 45-28 = 17
m<2 = 7(7) + 24 = 49 + 24 = 73
The light pole would be 4 ft long because:
135/15= 9. 36/9= 4ft
Answer: 9lb 3oz
Step-by-step explanation:
1. Add the pounds together first: 8lb
2. Then the ounces but there is over 16 ounces and 16 ounces make a pound. There is 19 ounces. So you can make ONE extra pound out of the 19 ounces. You would subtract: 19-16.
3. You have 3 left over: You can't make another pound so leave it as it is.
4. Add the extra pound to the 8 pounds and you have 9.
5. Then put the ounces with it and the answer is : 9lb 3oz
Answer:
In the study of probability theory, the central limit theorem (CLT) states that the distribution of sample means approximates a normal distribution. The average is a result of common characteristic within the group. As a general rule, sample sizes equal to or greater than 30 are deemed sufficient for the CLT to hold, anything less - ie; daily d=20 x 1ph may mean less cars ) it becomes a general rule, where sample sizes equal to or greater than 30 are deemed sufficient for the CLT to hold
Step-by-step explanation:
