Answer:
a) X[bar]=93
b)S=5.39
Step-by-step explanation:
Hello!
<em>A simple random sample of 5 months of sales data provided the following information: Month: 1 2 3 4 5 Units Sold: 94 100 85 94 92 </em>
<em />
<em>a. Develop a point estimate of the population mean number of units sold per month. </em>
The variable of interest is:
X: Number of sales per month.
A random sample of n=5 months was taken, for each month, the number of units sold was recorded. To calculate the mean of the sample you have to add all the observed frequencies (Units Sold) by the sample size (n)
X[bar]= ∑X/n= 465/5=93
You can say that, on average, 93 units were sold over the 5-month period.
<em>b. Develop a point estimate of the population standard deviation.</em>
To calculate the sample standard deviation you have to calculate the variance and then its square root:
![S^2= \frac{1}{n-1}[sumX^2-\frac{(sumX)^2}{n} ]](https://tex.z-dn.net/?f=S%5E2%3D%20%5Cfrac%7B1%7D%7Bn-1%7D%5BsumX%5E2-%5Cfrac%7B%28sumX%29%5E2%7D%7Bn%7D%20%5D)
∑X= 465
∑X²= 43361
![S^2= \frac{1}{4}[43361-\frac{(465)^2}{5} ]= 29](https://tex.z-dn.net/?f=S%5E2%3D%20%5Cfrac%7B1%7D%7B4%7D%5B43361-%5Cfrac%7B%28465%29%5E2%7D%7B5%7D%20%5D%3D%2029)
S= √29= 5.385≅ 5.39
I hope this helps!
The answer should be A.
When we see the equation y=a^x we can relate to all the exponential functions, however, when the problem asked what points does all equations in that form pass through. I was instantly reminded by two facts.
One is that any number to the first is equal to itself. In other words, a^1=a
Another is that any number to the zero is equal to 1. a^x=1
if that is true, 1 will always be the x value since y=a^x and 0 will always be the x value because that is how y can be equal to one.
therefore, the answer is A: (0,1)
Answer:
Methods of obtaining a sample of 600 employees from the 4,700 workforce:
Part A: The type of sampling method proposed by the CEO is Convenience Sampling.
Part B: When there are equal number of participants in both campuses, stratification by campus would give a more precise approximation of the proportion of employees who are satisfied with the cleanliness of the breakrooms than stratification by gender. Another method to ensure that stratification by campus gives a more precise approximation of the proportion of employees who are satisfied with the cleanliness of the breakrooms than stratification by gender is to ensure that the sample is proportional to the proportion of each campus to the whole population or workforce.
Step-by-step explanation:
A Convenience Sampling technique is a non-probability (non-random) sampling method and the participants are selected based on availability (early attendees). The early attendees might be different from the late attendees in characteristics such as age, sex, etc. Therefore, sampling biases are present. All non-probability sampling methods are prone to volunteer bias.
Stratified sampling is more accurate and representative of the population. It reduces sampling bias. The difficulty arises in choosing the characteristic to stratify by.
Answer:
The answer is the top right one since the total $96.35 is on the deposit side.
( i did this before and got it right btw)
Answer:
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