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3 years ago

The product of 5 and m squared,increased by the sum of the square of m and 5

Mathematics

2 answers:

ioda3 years ago

8 0

20 is the answer for that.

Harrizon [31]3 years ago

5 0

The product (multiplication) of 5 and m squared (²) increased (addition) by the sum (addition) of the square (²) of m and 5.

(5m²) + (m² + 5)

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marishachu [46]

Answer:

16.27

Step-by-step explanation:

if 1000m rep 1km

therefore :

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=16.277 ms

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2 years ago

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den301095 [7]

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2 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

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$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

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Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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2 years ago

From a well shuffled deck of 52 cards, the probability of NOT drawings a red-face card is ______.

Gnom [1K]

Answer:

Option "d" might be 11/13

Step-by-step explanation:

Red face cards=8. ( heart and Diamond)

Remove this 8 cards from 52 cards which gives

=>44

Toal cards =52

PROBABILITY = 44/52=>11/13

5 0

3 years ago

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andrew-mc [135]

Answer:

x=5

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Step-by-step explanation:

I just took this!

Hope I helped

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2 years ago