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Mazyrski [523]
3 years ago
13

The product of 5 and m squared,increased by the sum of the square of m and 5

Mathematics
2 answers:
ioda3 years ago
8 0
20 is the answer for that.
Harrizon [31]3 years ago
5 0
The product (multiplication) of 5 and m squared (²) increased (addition) by the sum (addition) of the square (²) of m and 5.

(5m²) + (m² + 5)
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Answer:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

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(b)

c = e-1 \\ = 1.71828

Step-by-step explanation:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

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(b)

You are looking for a point c   such that

\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}

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