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attashe74 [19]
3 years ago
6

Rounding up 3.82 inches

Mathematics
1 answer:
Vladimir79 [104]3 years ago
7 0
Nearest Tenth, Hundred?
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Comparing Leaking Pool Problem
Blababa [14]

Answer:

<em>Pool 1 leaks faster than pool 2.</em>

Step-by-step explanation:

<u>Rates of change</u>

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h

Pool 2:

\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0
3 years ago
Which Factors would simplify in this expression?
kolbaska11 [484]

Answer:

(x+6)

Step-by-step explanation:

because you have ( x+6) on bottom of the first equation and on the top on the second equation

7 0
3 years ago
The area of the bottom of a shoebox can be written as a(x) = 2x2 - 4 and the height of the shoebox can be written as h(x) = 3x +
Helga [31]

Answer:V(x) = 6x³ + 4x² - 12x - 8

Step-by-step explanation:

The shoe box can either be cube shaped or cubiod shaped. The volume of the box is length × breadth × height

Since Area = Length × Breadth

Volume = Area × Height

V(x) = A(x) × H(x)

A(x) = 2x² - 4

H(x) = 3x + 2

V(x) = (2x² - 4)(3x + 2)

V(x) = 6x³ + 4x² - 12x - 8

8 0
3 years ago
Use your knowledge of scientific notation, SI prefixes, conversion factors, and
mixas84 [53]
1 x 10^10 or 10000000000
4 0
3 years ago
Suppose your car gets 28 miles per gallon of gasoline, and you are driving at 55 miles per hour. Using unit analysis, find the a
pentagon [3]
<h3>Answer:</h3>

1 27/28 ≈ 1.964 gallons/hour

<h3>Step-by-step explanation:</h3>

You want gallons in the numerator of your unit rate, but that unit is in the denominator of the mileage rate. So, the computation must involve division by 28 mpg. Hours is already in the denominator of 55 mph, so the computation will involve multiplication by that rate.

... (55 mi/h)/(28 mi/gal) = (55 mi/h)·(1 gal/(28 mi)) = 55/28 gal/h

... = 1 27/28 gal/h

7 0
3 years ago
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