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3 years ago

9

Hi can you guys help me. The topic is similiar shapes in this case triangles do you guys know how to find a length. I got some p

ictures. I really appreciate.

1 answer:

Airida [17]3 years ago

4 0

PR=18mm
AB=7mm

All lengths of triangle PRQ are twice the lengths of ACB

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ale4655 [162]

Answer:

$Area = 58 \ units^2$

Step-by-step explanation:

We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:

$a^2+b^2=c^2$

In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:

$3^2+7^2=c^2$

$9+49=c^2$

$c^2=58$

$c=\sqrt{58}$

Since the area of a square is the side length square then...

$Area =( \sqrt{58} )^2$

The square root and the squared cancel out giving us...

$Area = 58 \ units^2$

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Step-by-step explanation:

I got it right on edg

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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