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3 years ago

Find the 35th term in the arithmetic sequence: -10,-14,-18,-22,..

Mathematics

1 answer:

ivanzaharov [21]3 years ago

3 0

The 35th term is -146 :)

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How much does 2 eggs cost if a case of eggs costs $25.23

amid [387]

Answer:

$4.20

Step-by-step explanation:

Number of eggs in a case - 12

Total cost of the case - $25.23

Cost of 1 egg - $2.10

25.23 ÷ 12 ≈ 2.10

2 eggs = $4.20

2.10 x 2 = 4.20

3 0

3 years ago

An archaeologist in turkey discovers a spear head that contains 32% of its original amount of c-14

leva [86]

Answer:

that means that the new ones contains c-14*32/100

Hope This Helps!!!

8 0

2 years ago

Twice Jack's age plus 5 is 21. Write and solve an equation. How old is Jack?

Aleksandr-060686 [28]

2j+5=21
2j=16
j=8

<span>Jack is 8 years old.
</span>
Hope This Helped! :3

7 0

4 years ago

Read 2 more answers

A chain lying on the ground is 10 m long and its mass is 70 kg. How much work (in J) is required to raise one end of the chain t

DerKrebs [107]

Answer:

$W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J$

Step-by-step explanation:

Data Given: m = 70 kg , g = 9.8 ms^-2, h =10m.

For this case we can use the following formula:

$W = \int_{x_i}^{x_f} F(x) dx$

For this case we need to find an expression for the force in terms of the distance. And since on this case the total distance is 10 m long we can write the expression like this:

$F(x) = \frac{ma}{10m}= \frac{mg}{10m} x$

The only acceleration on this case is the gravity and if we replace the values given we got:

$\frac{70 kg *9.8 m/s^2}{10m} x=68.6 x\frac{kg}{s^2}$

Now we can find the required work with the following integral:

$W= 68.6 \frac{kg}{s^2} \int_{0}^4 x dx$

$W= 34.3 \frac{kg}{s^2} x^2 \Big|_0^4$

$W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J$

7 0

4 years ago

How many hundred thousand people living in the word are living in poverty, given that n people in the world are living in povert

Diano4ka-milaya [45]

Answer:

$\frac{n}{100000}$

Step-by-step explanation:

Divide n by 100,000.

This gives us the "number of times 100,000 fits in n", or, "how many 100,000's n is", or as the hint says, "how many times larger n is than 100,000".

All represented by this formula:

$\frac{n}{100000}$

4 0

4 years ago