If B is between A and C, and AB=3x+1, BC=2x-7, and AC=24, then find the value of x and the value of AB
let assume AC is straight line and B is on line
AB + BC = AC
3x+1 +2x -7 = 24
5x -6 = 24
5x = 30
x = 6
One box has 15 flavor
And 1 child gets 3 flavors
So 1 box is enough for 5 children by dividing 15 by 3
There are 25 children so 25/5 = 5
So, Raymond has to buy 5 boxes
Well, there are an infinite amount...
1.) 2/5
2.) Multiply 2/5 by anything that equals 1... like 2/2. This will give you 4/10
3.) 6/15
4.) 8/20
etc...
Answer:
Wednesday
Step-by-step explanation:
A 18 sessions and we know that a session lasts 7 days. We also know that the sessions are grouped and that there is only a break after every 2 sessions. The sessions can only be held on weekdays which is 5 days. The first session starts on Friday. We need to determine the last day of the 18 sessions.
WE can assume that a break is a one day.
The first two sessions will be a total of 14 days and then a break. Friday adding 14 days will result in the first two sessions ending on Wednesday and a break day. The next two sessions will start Friday again.
Therefore the sessions are even number of 18 and therefore will always end on a Wednesday
Answer:
x = ± sqrt(43)
Step-by-step explanation:
2x^2 - 28 = x^2 + 15
Subtract x^2 from each side
2x^2-x^2 - 28 = x^2-x^2 + 15
x^2 -28 = 15
Add 28 to each side
x^2 - 28 +28= 15+28
x^2 = 43
Take the square root of each side
sqrt(x^2) = ± sqrt(43)
x = ± sqrt(43)
