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3 years ago

A rectangle is shown. The length of the rectangle is labeled 18 inches. The width of the rectangle is labeled 6 inches.

2 answers:

6 0

18 in and 6 in enlarged by 7:2
it will get bigger so 9:12 and 3:9 are not the answers
18×7/2 = 9×7=63 in
6×7/2= 3×7=21in

Airida [17]3 years ago

3 0

I think the answer is D.

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Which expression is equivalent to

cestrela7 [59]

Answer:

Step-by-step explanation:

When 3 is squared, it becomes 9. That means that both A and B are incorrect.

The powers on u and v are doubled not added to become u^6 and v^8 so that makes C the only possible answer.

4 0

3 years ago

In fig. AB = AC, D is the midpoint of BC. (i)Is  ADB ADC (ii) Is ∠B =∠C?

dexar [7]

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

$\triangle$ ADB $\cong\triangle$ ADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

3 0

3 years ago

the area of a triangle is 6 and 3/8 square yards. The height of the triangle is 2 and 1/2 yards. What is the length of the base

Otrada [13]

Solution:

Note that:

Area of triangle = 6 3/8 yd²
Height of triangle = 2 1/2
Area of triangle = 1/2 x base x altitude

Use the formula to find the base of the triangle.

1/2 x base x altitude = 6 3/8 yd²
=> 1/2 x base x 2 1/2 = 6 3/8 yd²
=> 1/2 x base x 5/2 = 6 3/8 yd²
=> 5/4 x base = 6 3/8 yd²
=> base = 6 3/8 ÷ 5/4 yd
=> base = 51/8 x 4/5 yd
=> base = 51/2 x 1/5 yd
=> base = 51/10 yd

The length of the base is 51/10 yards.

8 0

2 years ago

Read 2 more answers

What is the quotient of the following in simplest form? 5/9 divided by 2/3

Assoli18 [71]

Answer:

5/6

Step-by-step explanation:

You write the question as such: 5/9 divided by 2/3.

After that, you keep the first fraction, flip the sign and the fraction.

You will get: 5/9 multiplied by 3/2.

When you get this, you then cross multiply and simplify as such.

5/3 multiplied by 1/2.

5/6 would be your solution.

4 0

2 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago