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artcher [175]
3 years ago
14

Please help as soon as possible

Mathematics
1 answer:
Mice21 [21]3 years ago
4 0
1 kilometer = 1000 meters so 12 kilometers = 12000 meters

10 laps (400 meters/lap) = 4000 meters

12000/4000 = 3

Answer: 3 days
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Select the statement that correctly describes the expression below.
timama [110]

Answer:

B

Step-by-step explanation:

The product of the difference of x and 5 and the sum of x and 3

7 0
3 years ago
Need help solving this problem
Molodets [167]

Answer:

Step-by-step explanation:

q is TFTF

~q use negation, not q so is the opposite of q : FTFT

p↔~q use biconditional ,and will be True only is both statements are T or both are F

p values are TTFF ↔~q values are FTFT : FTTF

(p↔~q )∧~q use conjunction, that is True only if both statements are T

(p↔~q ) values are FTTF ∧~q values are  FTFT : FTFF

(p↔~q )∧~q → p use a conditional statement, where only True False will give a F

(p↔~q )∧~q values are FTFF → p values are TTFF : TTTT

4 0
2 years ago
What is 3 minus the exponet of 5
xz_007 [3.2K]

I'm going to assume you mean 3 to the power negative 5.

3^-5

Use rule [ x^-y = 1/x^y ]

3^-5 = 1/3^5 = 1/243

Best of Luck!

4 0
3 years ago
Read 2 more answers
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0
3 years ago
Need help on 11,12,13,14,15
const2013 [10]

Not sure what 14 is asking?

15 would be 16.

The square root of width squared plus length squared equals the diagonal.

So if you just change the order of the equation you can find the length.

Double check it by doing it both ways to see if your answer is right.

7 0
2 years ago
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