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Paha777 [63]
3 years ago
12

What is an equation, in standard form, of the line through (1,7) and (-2, -3)?

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Step-by-step explanation:

The equation of a line is 6x-2y=12. find the x-intercept and the y-intercept. a. x = -2 , y= 6 b. x = 2 , y= -6 c. x = -2 , y= -6 a. x = 2 , y= 6 which shows the line 3x -2y = -18 in slope-intercept form? y=3/2x+9 y=2/3x+9 y=-3/2x-9 y=2/3x-9 a line passes through the point (-1,3) and has a slope of -2. what is the equation of the line in slope-intercept form? y=2x+5 y=-2x+5 y=2x+1 y=-2x+1 a line passes through the points (1,7) and (-4,-3). what is the equation of the line in standard form? 4x-2y=10 4x+2y=10 4x-2y=-10 4x+2y=-10 which points are a solution to the inequality < −3+4? (choose all that apply) (select all that apply.) (0,4) (-2,7) (3,-4) (-1,-5)

mr Goodwill [35]3 years ago
4 0

Answer: -23

Step-by-step explanation:

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Which statement is false A the inequality sign alwats opens up to the largers number. B the greater number in the equality is al
Hatshy [7]

Answer:

D inequality sign always open up to a smaller number

Step-by-step explanation:

8 0
3 years ago
The square root of 61 is in between 2 integers what are they
swat32
One way is to estimate
1^2=1
2^2=4
3^2=9
4^2=16
5^2=25
6^2=36
7^2=49
8^2=64
the number 61 is between 49 and 64 therefor the square root of 61is between the intigers 7 and 8 or -7 and -8
8 0
3 years ago
A math test is worth 100 points and has 38 problems. each problem is worth either 5 points or 2 points. how many problems of eac
blondinia [14]
Hey there,
There are 2 ways
1st way:
Since there are 8 5 point problems, 38 - 8 = 30, will give you the 2 point problems.

2nd way: 
8 x 5 = 40
100 - 40 = 60
60 / 2 = 30
Thus there are 30, 2 point problems.

Hope this helps :))

~Top
4 0
3 years ago
Read 2 more answers
The frequency table below displays 17 students'
vazorg [7]
Yes, because the data can be displayed by a relative frequency compared with the whole.
3 0
2 years ago
How many roots does this has?<br>x^2+(2√5x)+2x=-10​<br>find Discriminant
Alexxandr [17]

Given:

The equation is

x^2+(2\sqrt{5})+2x=-10

To find:

The number of roots and discriminant of the given equation.

Solution:

We have,

x^2+(2\sqrt{5})x+2x=-10

The highest degree of given equation is 2. So, the number of roots is also 2.

It can be written as

x^2+(2\sqrt{5}+2)x+10=0

Here, a=1, b=(2\sqrt{5}+2), c=10.

Discriminant of the given equation is

D=b^2-4ac

D=(2\sqrt{5}+2)^2-4(1)(10)

D=20+8\sqrt{5}+4-40

D=8\sqrt{5}-16

D\approx 1.89>0

Since discriminant is 8\sqrt{5}-16\approx 1.89, which is greater than 0, therefore, the given equation has two distinct real roots.

3 0
3 years ago
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