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2 years ago

12

What is an equation, in standard form, of the line through (1,7) and (-2, -3)?

2 answers:

Dvinal [7]2 years ago

8 0

Step-by-step explanation:

The equation of a line is 6x-2y=12. find the x-intercept and the y-intercept. a. x = -2 , y= 6 b. x = 2 , y= -6 c. x = -2 , y= -6 a. x = 2 , y= 6 which shows the line 3x -2y = -18 in slope-intercept form? y=3/2x+9 y=2/3x+9 y=-3/2x-9 y=2/3x-9 a line passes through the point (-1,3) and has a slope of -2. what is the equation of the line in slope-intercept form? y=2x+5 y=-2x+5 y=2x+1 y=-2x+1 a line passes through the points (1,7) and (-4,-3). what is the equation of the line in standard form? 4x-2y=10 4x+2y=10 4x-2y=-10 4x+2y=-10 which points are a solution to the inequality < −3+4? (choose all that apply) (select all that apply.) (0,4) (-2,7) (3,-4) (-1,-5)

mr Goodwill [35]2 years ago

4 0

Answer: -23

Step-by-step explanation:

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sertanlavr [38]

Answer:

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2 years ago

32. Find the ratio of the side lengths of the small triangle to the large

kupik [55]

Answer:

2/3

Step-by-step explanation:

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1 year ago

How much kinetic energy does a 80 kg man have while running at 1.5 M/S

Anni [7]

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3 years ago

Complete the identity

spin [16.1K]

Answer: $cos(\pi-x)=-cos(x)$

Step-by-step explanation:

We need to apply the following identity:

$cos(A - B) = cos A*cos B + sinA*sin B$

Then, applying this, you know that for $cos(\pi-x)$ :

$cos(\pi-x)=cos(\pi)*cos(x)+sin(\pi)*sin(x)$

We need to remember that:

$cos(\pi)=-1$ and $sin(\pi)=0$

Therefore, we need to substitute these values into $cos(\pi-x)=cos(\pi)*cos(x)+sin(\pi)*sin(x)$ .

Then, you get:

$cos(\pi-x)=(-1)*cos(x)+0*sin(x)$

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2 years ago

What is 714 divided by 14?

ivanzaharov [21]

Answer:

51

Step-by-step explanation:

Hope this helps

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2 years ago

Read 2 more answers