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Snowcat [4.5K]
3 years ago
11

7 feet = inches round answer two decimal places

Mathematics
1 answer:
FrozenT [24]3 years ago
4 0

7 feet =84 inches


Round two decimal places will be 84.00

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How many 3/4 foot pieces can clark cut out from the 7 1/2 feet of wire
ivolga24 [154]
(7 1/2) / (3/4) = 
(15/2) / (3/4) =
15/2 * 4/3 =
30/3 =
10 <== there will be 10 three-fourth ft pieces
7 0
3 years ago
What is 6.564671128 x 10^-7 meters converted into nanometers?
fomenos

Answer:

656.4671128 nanometer

Step-by-step explanation:

1 nano meter = 10 ^-9 meter

Now given 6.564671128 × 10^ -7 meters

so in nano meter ,

\frac{6564671128 times 10^-7}{10^9}

= 656.4671128 × 10^-9 meter

= 656.4671128 nanometer    Answer

3 0
3 years ago
What error did Clyde make? And what is the correct simplified form
romanna [79]

Answer:

Clyde added -8+(-2), your supposed to multiply -8*(-2) the answer is j^16

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
All the students in a school were weighed. Their average weight was 30.8 kilograms, and their total weight was 16,293.2 kilogram
Zinaida [17]

Answer: 529 students

Step-by-step explanation:

To solve this, we will be using the formula for finding averages:

> (total sum of student weights) ÷ (total sum of students) = (average of student weights)

Plugging in the values that are given in the problem, you get:

> 16,293.2 ÷ x = 30.8

Where x is equal to the total sum of students. From here, it's a simple equation to isolate x, and find out what numerical value x is equal to. In case you are unsure how to do this, I've created a clear step by step process for how to do this (NOTE: The slash represents division, while the asterisk represents multiplication.):

> 16,293.2 / x = 30.8

> (16,293.2 / x) * x = (30.8) * x

> 16,293.2 = 30.8 * x

> (16,293.2) / 30.8 = (30.8 * x) / 30.8

> 529 = x

In total, there are 529 students in the school.

7 0
2 years ago
4x^2 = 92 + 7x solve the equation using the guadratic formula, show all work
katovenus [111]
4x^2=92+7x\ \ \ \ |-4x^2\\\\-4x^2+7x+92=0\\\\a=-4;\ b=7;\ c=92\\\\b^2-4ac=7^2-4\cdot(-4)\cdot92=49+1472=1521\\\\\sqrt{b^2-4ac}=\sqrt{1521}=39\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-7-39}{2\cdot(-4)}=\dfrac{-46}{-8}=\dfrac{23}{4}\\\\x_2=\dfrac{-7+39}{2\cdot(-4)}=\dfrac{32}{-8}=-4


\text{Answer:}\ A.\ \left\{\dfrac{23}{4};\ -4\right\}
4 0
3 years ago
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