ANSWER:
x=10
STEP BY STEP:
Hope this helps. :)
10 minutes at 2 meters/second
1 minute = 60 seconds
10 minutes = 600 seconds.
600 seconds at 2 meters/second
2 meters × 600 = total distance
1200 meters <em>or</em> 1.2 km
The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system
Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999
The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
Answer:
0.75
Step-by-step explanation:
Answer:
The mean is 15.93 ounces and the standard deviation is 0.29 ounces.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
7% of the bottles containing this soft drink there are less than 15.5 ounces
This means that when X = 15.5, Z has a pvalue of 0.07. So when X = 15.5, Z = -1.475.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![-1.475 = \frac{15.5 - \mu}{\sigma}](https://tex.z-dn.net/?f=-1.475%20%3D%20%5Cfrac%7B15.5%20-%20%5Cmu%7D%7B%5Csigma%7D)
![15.5 - \mu = -1.475\sigma](https://tex.z-dn.net/?f=15.5%20-%20%5Cmu%20%3D%20-1.475%5Csigma)
![\mu = 15.5 + 1.475\sigma](https://tex.z-dn.net/?f=%5Cmu%20%3D%2015.5%20%2B%201.475%5Csigma)
10% of them there are more than 16.3 ounces.
This means that when X = 16.3, Z has a pvalue of 1-0.1 = 0.9. So when X = 16.3, Z = 1.28.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.28 = \frac{16.3 - \mu}{\sigma}](https://tex.z-dn.net/?f=1.28%20%3D%20%5Cfrac%7B16.3%20-%20%5Cmu%7D%7B%5Csigma%7D)
![16.3 - \mu = 1.28\sigma](https://tex.z-dn.net/?f=16.3%20-%20%5Cmu%20%3D%201.28%5Csigma)
![\mu = 16.3 – 1.28\sigma](https://tex.z-dn.net/?f=%5Cmu%20%3D%2016.3%20%E2%80%93%201.28%5Csigma)
From above
![\mu = 15.5 + 1.475\sigma](https://tex.z-dn.net/?f=%5Cmu%20%3D%2015.5%20%2B%201.475%5Csigma)
So
![15.5 + 1.475\sigma = 16.3 – 1.28\sigma](https://tex.z-dn.net/?f=15.5%20%2B%201.475%5Csigma%20%3D%2016.3%20%E2%80%93%201.28%5Csigma)
![2.755\sigma = 0.8](https://tex.z-dn.net/?f=2.755%5Csigma%20%3D%200.8)
![\sigma = \frac{0.8}{2.755}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B0.8%7D%7B2.755%7D)
![\sigma = 0.29](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.29)
The mean is
![\mu = 15.5 + 1.475\sigma = 15.5 + 1.475*0.29 = 15.93](https://tex.z-dn.net/?f=%5Cmu%20%3D%2015.5%20%2B%201.475%5Csigma%20%3D%2015.5%20%2B%201.475%2A0.29%20%3D%2015.93)
The mean is 15.93 ounces and the standard deviation is 0.29 ounces.