the coordinates of the endpoints of CE are C(-3, -7) and E(7, -2). point M (3, -4) is on CE. what is the ratio of CM:ME?
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Answer:
m∠Q ≈ 53°
Step-by-step explanation:
To find the measure of ∠Q, the law of cosines will need to be used. Lowercase letters represent the side lengths, while upper case letters represent angles.
In this situation, 'A' will be ∠Q. Therefore:
17² = 18² + 20² -2(18)(20)cosQ
Simplify:
289 = 324 + 400 -2(360)cosQ
Continue simplifying down:
-435 = -720cosQ
Divide both sides by '-720':
0.604 = cosQ
m∠Q ≈ 52.83 or 53° rounded to the nearest whole degree.
You can graph that by looking at the y-intercept first. That's where you start to put a point in the coordinate plane or graph.
So go down 1 below 0.
Next, look at the slope.
We know that y = -2x - 1 is in slope intercept form (y = mx+b)
So -2 is our slope. It will be -2/1 because we need a fraction to graph the rise over run and all whole numbers can be a fraction by making 1 as their denominator.
Look at the attachment.
Starting from -1 (y-intercept), go down 2 (-2) then right 1 (1).
To complete the line above, keep the same value and reverse their sign/symbol. So -2/1 will be 2/-1. It goes up 2 then left 1.
I hope you understand and find this answer the most helpful! :)
So go down 1 below 0.
Next, look at the slope.
We know that y = -2x - 1 is in slope intercept form (y = mx+b)
So -2 is our slope. It will be -2/1 because we need a fraction to graph the rise over run and all whole numbers can be a fraction by making 1 as their denominator.
Look at the attachment.
Starting from -1 (y-intercept), go down 2 (-2) then right 1 (1).
To complete the line above, keep the same value and reverse their sign/symbol. So -2/1 will be 2/-1. It goes up 2 then left 1.
I hope you understand and find this answer the most helpful! :)