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shutvik [7]
3 years ago
13

The area of a square can be found using the equation A = s², where A is the area and s is the measure of one side of the square.

Mathematics
2 answers:
Anettt [7]3 years ago
8 0

we know that

The area of a square is equal to

A=s^{2}

where

s is the length side of a square

To solve for a side length of a square, isolate the variable s

A=s^{2}

square root both sides

s=\sqrt{A}

In this problem we have

A=227\ in^{2}

substitute in the formula to find s

s=\sqrt{227}\ in

therefore

the answer in the attached figure


juin [17]3 years ago
4 0
The answer would be s=square root of 227 squared inches squared. (the first one) 
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Which expression is equivalent to 3(2x−4)+4x−2
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I hope this helps you



3.2x-3.4+4x-2


6x-12+4x-2


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Setting:
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A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.

b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.

c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%

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3 years ago
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What percentage is the fraction ‘2/4’ equal to ?<br> A. 30% <br> B. 20% <br> C. 50% <br> D. 40%
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Answer: C.) 50%


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3 years ago
What is the sum of the first 51 consecutive odd positive integers?
Angelina_Jolie [31]
We call:

a_{n} as the set of <span>the first 51 consecutive odd positive integers, so:

</span>a_{n} = \{1, 3, 5, 7, 9...\}

Where:
a_{1} = 1
a_{2} = 3
a_{3} = 5
a_{4} = 7
a_{5} = 9
<span>and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

</span>a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}
<span>
Then:

</span>a_{n} = a_{1} + (n-1)d
<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

</span>S_{k} = ( \frac{a_{1} +  a_{k}}{2}  ).k
<span>
Therefore, we need to find:
</span>a_{k} =  a_{51}  

Given that a_{1} = 1, then:

a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1

Thus:
a_{k} = a_{51} = 2(51)-1 = 101

Lastly:

S_{51} = ( \frac{1 + 101}{2} ).51 = 2601 

4 0
3 years ago
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