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olganol [36]
3 years ago
11

Is (0,-4), (-3,-10), (2,0) colinear?

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
6 0

Answer:

Yes its collinear

Step-by-step explanation:

Wewaii [24]3 years ago
4 0

Answer:

no it is not.

Step-by-step explanation:

We know this because they do not lay on the same line.

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Graph the line with slope −2 passing through the point , 5−1.
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<u>Answer:</u>

<u>y+1=-2(x-5)</u> - Point Slope Form

<u>y=-2x+9</u> - Slope Intercept Form

<u></u>

Step-by-step explanation:

We will be using point-slope formula, as attached in a picture below.

1) Plug in the slope -2 as "m" in point slope form, along with the two points, (5, -1)

<u>y+1=-2(x-5)</u>

2) Next, if you want to put the line into slope-intercept form, you will need to distribute -2 to x and -5:

y+1=-2x+10

3) Now, subtract 1 from both sides:

<u>y=-2x+9</u>

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Ira Lisetskai [31]

First of all, let's find the slope of line L. To find the slope of a line, you write it in the explitic form y = mx+q, and consider the coefficient m. So, we have

2x - 3y = 5 \iff 3y = 2x-5 \iff y = \dfrac{2}{3} x - \dfrac{5}{3}

So, the slope of line L is 2/3.

Two lines are parallel if they have the same slope. So, line M has slope 2/3 as well, and we know that it passes through the point (3, -10).

When you are given the slope m and a point (x_0,y_0) of a line, its equation is given by

y-y_0=m(x-x_0)

So, if you plug your values, you have

y+10 = \dfrac{2}{3}(x-3)

which you can simplify into

y+10 = \dfrac{2}{3}x-2

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