So the first thing we need to do is multiply 3*-5, since order of operations dictates it (PEMDAS)

Now, whenever we see a minus negative number, we can think of it as adding a positive number

Now we just add them together

23 is the answer
Answer:
c. 25
Step-by-step explanation:
BOTH SIDES HAVE X SO YOU PUT THEM IN A 1 EQUATION WAY AND SOLVE X:
4X+1=2X+23
4X-2X=23-1
2X=32
X= 32/2=11
THEN YOU GO TO THE BASE AND CHANGE X AND SOLVE THE EQUATION WITH X=11
3x11-8
33-8= 25=BASE
2x+y=9
3x+5y=19
I will do this problem in 2 ways. I.)Substitution II.)Elimination
Solution I.) Substitution
We can subtract 2x from both sides in the first equation.
y=9-2x
Now we can substitute the y in the second equation with 9-2x
3x+5(9-2x)=19
-7x+45=19
-7x=-26
x=26/7
y=9-2(26/7)=11/7
Solution II.)Elimination
We can multiply both side of first equation by 5 to get a 5y in both equations.
10x+5y=45
Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.
(10x+5y)-(3x+5y)=45-19
7x=26
x=26/7
2*26/7+y=9
y=11/7
Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.
Answer:
16.28 mph ; 79.38°
Step-by-step explanation:
Given the following :
Speed of child due east = 3mph
Speed of ship due North = 16mph
Relative speed of th child is obtained by using Pythagoras rule to find the hypotenus
Relative Speed = Sqrt(3² + 16²)
Relative Speed = sqrt(9 + 256)
= sqrt(265)
= 16.2788 mph
= 16.28 mph
From trigonometry ;
Tanθ = opposite / Adjacent
Tanθ = (16 / 3)
Tanθ = 5.333
θ = tan^-1(5.333)
θ = 79.379°
θ = 79.38°