Answer:
height = 20.5068 m
Step-by-step explanation:
Given the data in the question;
First, lets calculate the amplitude, midline and period of 8minutes
Amplitude = 35 / 2 = 17.5
|A| = 17.5
A = - 17.5 { since the wheel starts at 6 o clock }
midline C = (35/2) + 3
C = 17.5 + 3
C = 20.5
And period is 8 minutes
⇒ 2π/B = 8
8B = 2π
B = 2π/8 = π/4
So our equation will be in the form of;
y = h(t) = Acos(B×t) + C
∴ h(t) = -17.5cos( π/4×t) + 20.5
Now, How high are you off the ground after 6 minutes
⇒ height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( 4.71238898) + 20.5
height = -17.5 × cos( 4.712) + 20.5
height = -17.5 × -0.00038898 + 20.5
height = 0.0068 + 20.5
height = 20.5068 m
Y = 3x + 4
y = 3x + 7
3x + 4 = 3x + 7
3x - 3x = 7 - 4
0 = 3.....incorrect....this system has no solutions because ur lines are parallel and they never cross.
or look at it this way..
y = 3x + 4
y = 3x + 7
both have slopes of 3...but the y intercepts are different......when this happens, it means the lines are parallel with no solution
Answer/Step-by-step explanation:
Let's solve your equation step-by-step.
4−(2y+5)=3(1−4y)
Step 1: Simplify both sides of the equation.
4−(2y+5)=3(1−4y)
4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)
4+−1(2y)+(−1)(5)=3(1−4y)
4+−2y+−5=3(1−4y)
4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)
4+−2y+−5=3+−12y
(−2y)+(4+−5)=−12y+3(Combine Like Terms)
−2y+−1=−12y+3
−2y−1=−12y+3
Step 2: Add 12y to both sides.
−2y−1+12y=−12y+3+12y
10y−1=3
Step 3: Add 1 to both sides.
10y−1+1=3+1
10y=4
Step 4: Divide both sides by 10.
10y
10
=
4
10
y=
2
5
Answer:
y=
2/5
yw
Answer:
Mirandah added 5x and 9y, which she shouldn't do because one is y and the other is x, meaning they don't match.
There is no simplifying the equation. It should stay 5x + 9y - 4
If wrong, I apologize, but this should be correct.
