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Korolek [52]
2 years ago
6

Pls help I’ll brainlest ASAP

Mathematics
2 answers:
kherson [118]2 years ago
5 0
3/5 is the slop 3 up 5 over
Amanda [17]2 years ago
3 0
(-2,1) i think that’s the answer
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Identify the percent of change as an increase or a decrease.
vodomira [7]

Answer:

Increase

Step-by-step explanation:

The number gets larger. Increase means it gets larger, but decrease means it gets lower.

5 0
3 years ago
Find a in the figure below and place the value in the empty box
AleksAgata [21]

Answer:

a = 12m

Step-by-step explanation:

In order to solve this problem we will need to know the Pythagoras theorem that states that in a right angled triangle the square of the hypotenuse (the side opposite to the right angel) is equal to  the sum of the squares of the other two sides. This theorem can be written as an equation....

c^{2} = a^{2}  + b^{2}

Now we can see that we can easily find the missing value by using this theorem. We just have to substitute the values. And we get the following

c^{2} = a^{2} + b^{2}

a^{2} = c^{2} - b^{2}

a^{2} = 15^{2} - 9^{2}

a^{2} = 225 - 81

a^{2} = 144

a = \sqrt{144}

a = 12

7 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
MZAOB = 6x- 12°<br> mZBOC = 3x+ 30°<br> Find mZAOB:
Elanso [62]
The answer is 14 hope is right
4 0
3 years ago
Read 2 more answers
Please help me, it’s very important
gayaneshka [121]
2x2+6x+20 here is it
3 0
3 years ago
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