We have been given graph of a downward opening parabola with vertex at point
. We are asked to write equation of the parabola in standard form.
We know that equation of parabola in standard form is
.
We will write our equation in vertex form and then convert it into standard form.
Vertex for of parabola is
, where point (h,k) represents vertex of parabola and a represents leading coefficient.
Since our parabola is downward opening so leading coefficient will be negative.
Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:




Divide both sides by 
So our equation in vertex form would be
.
Let us convert it in standard from.



Therefore, the equation of function is standard form would be
.
16/-8=-2
Whenever dividing a -negative number and +positive number= number will be always -
3 3/7 / 1 1/7= 24/7 *7/8= 3 ( Cross out 7 and 7, divide by 1). Cross out 8 and 24 and divide by 8) ( Also always flip over the second fraction only when dividing)
3 3/7= 24/7 because multiply the denominator and whole number. 3*7=21
Add 21 with the numerator (3)= 21+3=24
-12.2 / (-6.1)=2
Whenever dividing two - negative numbers= + positive number
-2 2/5 / 4/5= -12/5*5/4=-3 Cross out 5 and 5- divide by 5. Cross out 4 and -12, divide by 4
Answers:
- 2 = 16/-8=-2
3= 3 3/7 /( dividing )1 1/7= 3
2= -12.2 / (-6.1)=2
-3=-2 2/5 / ( dividing) 4/5=-3
Obtuse, accute, obtuse, acute, A.
Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:


Z = 1.71
Z = 1.71 has a p-value of 0.9564.
1 - 0.9564 = 0.0436.
0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
More can be learned about the normal distribution at brainly.com/question/24663213
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Answer:
EBD is 135, ABE is 45
Step-by-step explanation: