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Kay [80]
3 years ago
14

Help please fast!!!!!!!1

Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:b

Step-by-step explanation: i thinks its b

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Help help please please please
meriva
<h2>>> Answer </h2>

________

\:

4x + 2 > 14

4x > 14 - 2

4x > 12

x < 12 ÷ 4

x < 3

3 0
3 years ago
Read 2 more answers
The imposition of an integer restriction is necessary for models where:
Elena L [17]

Answer: goodluck i just needed points sorry :(

Step-by-step explanation:

idk sorry

5 0
3 years ago
Vladimir says that the equation of the line that passes through points above Robyn says that the line passes through the points
aleksley [76]

Answer:

Both are correct

Step-by-step explanation:

The Line has the following equation: y= 1+4/5 x

So we need to know which points: (-5,-3) and (10,9), (-10,-7). (-15, -11) are part of the line

For instances, lest start by evaluating (-15,-11) in y=1+4/5 x

this leaves us to the following operation: -11=1+4/5 * (-15)

-11=1-4*3 resulting in a equality -11=-11, this point does belong to the line

Repeat the above for all of the remaining points and you will get the same conclusion, that is we Vladimir and Robyn are correct.

8 0
3 years ago
If one of the factors of 200 is 40, what is the other factor that would create this product?
Anit [1.1K]
The answer would be 5 cuz 5 x 40 = 200
8 0
3 years ago
'Polonium-210 is a radioactive substance with a half-life of 138 days. If a nuclear
Tatiana [17]

Answer:

  • <u>59.0891 g (rounded to 4 decimal places)</u>

Explanation:

<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.

Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:

  • A=A_0\cdot (1/2)^n

Where:

  • A is the amount that remains of the substance after n half-lives have elapses, and
  • A₀ is the starting amount of the substance.

In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:

  • 330 days / 138 days = 2.3913

Therefore, the amount of polonium-210 that will be left in 330 days is:

  • A=310{g}\cdot (1/2)^{2.3913}=59.0891g
5 0
3 years ago
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