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Kay [80]
3 years ago
14

Help please fast!!!!!!!1

Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:b

Step-by-step explanation: i thinks its b

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in a certain game, a fair die is rolled and a player gains 20 points if the die shows a 6. if the die does not show a 6, the pla
BaLLatris [955]

The expected gain or loss is an illustration of mean and expected values.

The expected total gain is 83 points

The given parameters are:

  • Addition of 20 points for rolling a 6
  • Removal of 3 points for not rolling a 6

The probability of rolling a 6 in a fair die is 1/6.

The probability of not rolling a 6 in a fair die is 5/6.

So, the expected gain in each game is:

\mathbf{E(x) = 20 \times \frac 16 - 3 \times \frac 56}

\mathbf{E(x) = \frac{20}6 -  \frac{15}6}

Take LCM

\mathbf{E(x) = \frac{5}6}

\mathbf{E(x) = 0.83}

The number of games is 100.

So, the expected gain is:

\mathbf{Gain = 100 \times 0.83}

\mathbf{Gain = 83}

Hence, the expected total gain is 83 points

Read more about expected value at:

brainly.com/question/13499496

5 0
3 years ago
64x​^2-81 what’s the answer ?
pychu [463]

Answer:

(8x-9)(8x+9)

Step-by-step explanation:

64x^2 - 81

Rewriting

(8x)^2 - 9^2

We recognize that this is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(8x-9)(8x+9)

3 0
3 years ago
Read 2 more answers
the number of bacteria in a culture is growing at a rate of 1500e^(3t/4) per unit of time t. at t=0, the number of bacteria pres
makkiz [27]
Quarter 200 of per unit =3t)4^
5 0
4 years ago
Read 2 more answers
One-tenth x fewer than the sum of one-fifth y and 2x
In-s [12.5K]
(1/10 (x)) fewer than the sum of 1/5 (y) and 2x so
1/10 (x)=1/10 times x=x/10
1/5 (y)=y/5
-x/10+y/5+2x
simplified it is
19x/10+y/5
8 0
4 years ago
A guy wire makes a 65° angle with the ground. walking out 37 feet further from the tower, the angle of elevation to the top of t
kicyunya [14]

Let's call the height of the tower h and the distance from the 65 degree angle to the base of the tower d.

We get two equations:

\tan 65^\circ = \dfrac h d

\tan 39^\circ = \dfrac{h}{d+37}

h = d \tan 65^\circ = (d+37) \tan 39^\circ

d(\tan 65 - \tan 39) = 37 \tan 39

d = \dfrac{37 \tan 39}{\tan 65 - \tan 39}

h = d \tan 65 = \dfrac{37 \tan 39 \tan 65}{\tan 65 - \tan 39}

h \approx 48.1 \textrm{ feet}

Answer: 48

3 0
4 years ago
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