Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
<span>=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) </span>
<span>=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) </span>
<span>=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) </span>
<span>=(r+2)(r+10)/(r-10)</span>
Two sides are 34 and 14.
The third side can't be longer than (34 + 14) = 48, because the 34 and the 14
together could not reach from one end of it to the other.
The third side also can't be shorter than 20, because the 20 and the 14 together
could not reach from one end of the 34 to the other.
So 18 doesn't work. (18 + 14) = 32 ... they couldn't cover the 34 .
38+39+40 = 117.
So the first of the three numbers is 38.
Well i’m not sure on this but i got 18 for my answer instead of 10 so if u need any mode help im here
Answer:
f(10) = 3(10) - 2 = 28
Step-by-step explanation:
