Question

When 32.5g of carbon is heated with silicone dioxide, 28.8 g of carbon monoxide is produced. What is the percent yield of carbon monoxide?

Answer 1

Answer:

Percent yield of carbon monoxide is approximately 38%.

Explanation:

Given reaction : C + SiO₂ → Si + CO

On balancing it : 2C + SiO₂ → Si + 2CO

⇒ 2 mole of carbon produces 2 mole of carbon monoxide

or 2×12=24 g of carbon produces 2×(12+16)=56 g of carbon monoxide

⇒ Expected yield of carbon monoxide when 32.5g of carbon is heated with silicon dioxide is 32.5×$\frac{56}{24}$

⇒ Expected yield = $\frac{455}{6}$ = 75.8 g

Actual yield is given as 28.8 g

⇒ The percent yield of carbon monoxide = $\frac{Actual\ yield}{Expected\ yield}$×100

= $\frac{28.8}{75.8}$×100

≅38%