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Mrrafil [7]
3 years ago
6

When 32.5g of carbon is heated with silicone dioxide, 28.8 g of carbon monoxide is produced. What is the percent yield of carbon

monoxide?
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
5 0

Answer:

Percent yield of carbon monoxide is approximately 38%.

Explanation:

Given reaction : C + SiO₂ → Si + CO

On balancing it : 2C + SiO₂ → Si + 2CO

⇒ 2 mole of carbon produces 2 mole of carbon monoxide

or 2×12=24 g of carbon produces 2×(12+16)=56 g of carbon monoxide

⇒ Expected yield of carbon monoxide when 32.5g of carbon is heated with silicon dioxide is 32.5×\frac{56}{24}

⇒ Expected yield = \frac{455}{6} = 75.8 g

Actual yield is given as 28.8 g

⇒ The percent yield of carbon monoxide = \frac{Actual\ yield}{Expected\ yield}×100

= \frac{28.8}{75.8}×100

≅<u>38%</u>

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<h3>Balanced equation</h3>

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<h3>How to determine the volume of NH₃ produced</h3>

From the balanced equation above,

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We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:

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Finally, we shall determine the mass of NH₃ as follow:

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