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jonny [76]
3 years ago
7

how do different stimuli affect the survival behavior of an organism?THIS IS THE SECOND TIME IM ASKING PLZZZZ HELP ME

Chemistry
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

Organisms change their behavior in response to changes in the surrounding environment.

Explanation:

All living things can respond to stimuli in the exterier environment, It is a form of energy—light waves or sound vibrations, From what they sense they will make neccisary changes to their diet and or where they are located.

Such as winter weather which is a type of stimulus will cause some animals to start hibernating.

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The process of change in a population over time is called what?
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Microevolution

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Nuclear energy is currently used in which three kinds of vehicles?
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Nuclear power plants produce little to no greenhouse gas.

Nuclear power plants produce a large amount of energy for a small mass of fuel.

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Landslides and slumps are forms of ?
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18. Focal length is a length which lies between
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7 0
4 years ago
Consider the reaction. 2 Pb ( s ) + O 2 ( g ) ⟶ 2 PbO ( s ) An excess of oxygen reacts with 451.4 g of lead, forming 367.5 g of
Art [367]

Answer : The percent yield of the reaction is, 75.6 %

Solution : Given,

Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles

Now we have to calculate the moles of PbO

The balanced chemical reaction is,

2Pb(s)+O_2(g)\rightarrow 2PbO(s)

From the reaction, we conclude that

As, 2 mole of Pb react to give 2 mole of PbO

So, 2.18 mole of Pb react to give 2.18 mole of PbO

Now we have to calculate the mass of PbO

\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO

\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g

Theoretical yield of PbO = 486.1 g

Experimental yield of PbO = 367.5 g

Now we have to calculate the percent yield of the reaction.

\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100

\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%

Therefore, the percent yield of the reaction is, 75.6 %

3 0
4 years ago
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