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Yanka [14]
3 years ago
6

Chemical formula for an ionic compound

Chemistry
1 answer:
lawyer [7]3 years ago
5 0
The chemical formula for an ionic compound is metal + nonmetal = ionic
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Which will not appear in the equilibrium constant expression for the reaction below?
n200080 [17]

Answer:

[C] carbon solid

Explanation:

Pure solids and liquids are never included in the equilibrium constant expression because they do not affect the reactant amount at equilibrium in the reaction, thus since your equation has [C] as solid it will not be part of the equlibrium equation.

5 0
4 years ago
Alll moving objects have energy of _________
Natasha_Volkova [10]
All moving objects have kinetic energy.

Kinetic energy is the energy of motion, therefore if an object is moving it has kinetic energy.
3 0
3 years ago
If you have A 6-g sugar cube (C12H22011) and dissolved in a cup of hot tea. The
Iteru [2.4K]

The percentage of sugar in the solution is 1%

To solve this question, we need to find the percentage of 6 out of 600.

Data given;

  • mass of sugar = 6g
  • mass of solution = 600g
<h3 /><h3>What is Percentage</h3>

This is the rate or proportion of a substance in the total value and multiplied by 100.

The percentage of sugar in the solution is calculated by

\frac{6}{600} * 100 = 1 %

The percentage of sugar in the solution is 1%

Learn more about percentage here;

brainly.com/question/251701

8 0
3 years ago
Draw the condensed structural formula in the equation for the saponification of trimyristin with koh
Ludmilka [50]

Explanation: Saponification reaction is a reaction in which hydrolysis of fats takes place under basic conditions giving glycerol and a salt of corresponding fatty acid.

We are given a Fatty acid called as Trimyristin.

Its reaction with KOH leads to the formation of soap and is given by the equation:

Trimyristin+3 KOH\rightarrow Glycerol+Soap

C_{45}H_{86}O_6+3KOH\rightarrow C_3H_5(OH)_3+3CH_3(CH_2)_{12}CO_2K

The condensed structural formula for the equation is given in the image attached.

4 0
3 years ago
Read 2 more answers
What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch
sammy [17]

Explanation:

It is known that charge on xenon nucleus is q_{1} equal to +54e. And, charge on the proton is q_{2} equal to +e. So, radius of the nucleus is as follows.

            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

                 = 5.5 \times 10^{-15} m     (as 1 fm = 10^{-15})

Therefore, electrostatic repulsive force on proton is calculated as follows.

              F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

Putting the given values into the above formula as follows.

           F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

              = (9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}

              = (9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}

              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
4 years ago
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