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3 years ago

This is a serious question. What is 69 x 1 59/20 Will give brainliest

Mathematics

1 answer:

likoan [24]3 years ago

3 0

Answer:

10971/20

Step-by-step explanation:

69 * 159/20

69/1 * 159/20

69 * 159 = 10971

1 * 20 = 20

So the answer is basically 10971/20.

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Answer this please!!!

vivado [14]

Answer:

$40

Step-by-step explanation:

5 0

2 years ago

Simplify: 4(r + 1) + 3r A. 4r + 4 B. 5r + 1 C. 7r + 1 D. 7r + 4

klasskru [66]

Answer:

look in the explanation, it is in there

Step-by-step explanation:

i don't know if you are distributing or just using PEMDAS .

if you are distributing then: do in the equation 4(r + 1) + 3r.. do 4 x r and 4 x 1 , now you have 4r + 4 + 3r

7r +4

is what i got!

If you are doing PEMDAS then: first you do what is inside the perenthisis ()

4(r + 1) +3r changes into

4( r1 ) + 3r now you do multipulcation because that in the "M" in pemdas

4r + 3r, then if you are using like terms you would add them

i hope this helps you out!

6 0

3 years ago

Read 2 more answers

Add and Subtract Rational Expressions with a Common Denominator

Sladkaya [172]

Answer:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}$

Step-by-step explanation:

Simplifying Rational Expressions

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}$

Operating on the numerators:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}$

Removing parentheses:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}$

Simplifying:

$\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}$

The expression cannot be further simplified.

7 0

3 years ago

What is the center and radius of -10x = -121 - y2 - x2 -22y

OlgaM077 [116]

We need to find the center and the radius of

$-10x\: =\: -121\: -\: y^2\: -\: x^2\: -22y$

The general circle equation is the following

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center and

r is the radius

1. rearrange the equation

$(x^2-10x)+(y^2+22y+121)=0$

2. Add 25 on both sides

$(x^2-10x+25)+(y^2+22y+121)=25$

3. Factor

$(x-5)^2+(y+11)^2=5^2$

Now we have an equation that is very similar to the circle equation, so let's compare them

Center -> (h,k) = (5,-11)

radius -> r = 5

8 0

1 year ago

How many solutions does this system have?*

sweet-ann [11.9K]

Answer:

1 solution

Step-by-step explanation:

$y = - 3 \\ y = - x - 4 \\ = > - 3 = - x - 4 \\ = > - x - 4 + 3 = 0 \\ = > - x - 1 = 0 \\ = > - x = 1 \\ = > x = - 1$

4 0

3 years ago