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Pavlova-9 [17]
2 years ago
6

How to do this i need help

Mathematics
2 answers:
Anestetic [448]2 years ago
5 0

Answer: Do not take it

Step-by-step explanation:

Because 9 times eight is 72 and half of that is 36 so you if you take it you would make 108 but if you do not take the deal you will make 137

Flura [38]2 years ago
5 0

Answer:

the answer is No

Step-by-step explanation:

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Find the domain and range of the function
SVEN [57.7K]

Answer:

domain: (-∞ , ∞)

range: (-∞, 2]

Step-by-step explanation:

the domain is the set of values of what the x value can be. This function is parabolic and upside down, it can have a range of x values from - infinity to positive infinity. The function is most likely y=-x^2 +2

range is the output (y values) the function can possibly have. the max is 2 and includes 2 so we use bracket for that. The smallest y value can reach towards negative infinity.

Please give thanks by clicking the heart button! :)

3 0
3 years ago
Read 2 more answers
Please answer<br>Solve for the missing angles <br><br>1=<br><br>2=<br><br>3=<br><br>4=
prohojiy [21]

Answer:

correct answer is : To determine to measure of the unknown angle, be sure to use the total sum of 180°. If two angles are given, add them together and then subtract from 180°. If two angles are the same and unknown, subtract the known angle from 180° and then divide by 2.

8 0
2 years ago
Show your work<br> −126 = 14k
Yuliya22 [10]

Answer: k = -9

Step-by-step explanation:

-126 = 14k

-------  -------

 14     14

-126 divided by 14 = -9

k = -9

4 0
3 years ago
Find the sum or difference. a. -121 2 + 41 2 b. -0.35 - (-0.25)
s344n2d4d5 [400]

Answer:

2

Step-by-step explanation:

The reason an infinite sum like 1 + 1/2 + 1/4 + · · · can have a definite value is that one is really looking at the sequence of numbers

1

1 + 1/2 = 3/2

1 + 1/2 + 1/4 = 7/4

1 + 1/2 + 1/4 + 1/8 = 15/8

etc.,

and this sequence of numbers (1, 3/2, 7/4, 15/8, . . . ) is converging to a limit. It is this limit which we call the "value" of the infinite sum.

How do we find this value?

If we assume it exists and just want to find what it is, let's call it S. Now

S = 1 + 1/2 + 1/4 + 1/8 + · · ·

so, if we multiply it by 1/2, we get

(1/2) S = 1/2 + 1/4 + 1/8 + 1/16 + · · ·

Now, if we subtract the second equation from the first, the 1/2, 1/4, 1/8, etc. all cancel, and we get S - (1/2)S = 1 which means S/2 = 1 and so S = 2.

This same technique can be used to find the sum of any "geometric series", that it, a series where each term is some number r times the previous term. If the first term is a, then the series is

S = a + a r + a r^2 + a r^3 + · · ·

so, multiplying both sides by r,

r S = a r + a r^2 + a r^3 + a r^4 + · · ·

and, subtracting the second equation from the first, you get S - r S = a which you can solve to get S = a/(1-r). Your example was the case a = 1, r = 1/2.

In using this technique, we have assumed that the infinite sum exists, then found the value. But we can also use it to tell whether the sum exists or not: if you look at the finite sum

S = a + a r + a r^2 + a r^3 + · · · + a r^n

then multiply by r to get

rS = a r + a r^2 + a r^3 + a r^4 + · · · + a r^(n+1)

and subtract the second from the first, the terms a r, a r^2, . . . , a r^n all cancel and you are left with S - r S = a - a r^(n+1), so

(IMAGE)

As long as |r| < 1, the term r^(n+1) will go to zero as n goes to infinity, so the finite sum S will approach a / (1-r) as n goes to infinity. Thus the value of the infinite sum is a / (1-r), and this also proves that the infinite sum exists, as long as |r| < 1.

In your example, the finite sums were

1 = 2 - 1/1

3/2 = 2 - 1/2

7/4 = 2 - 1/4

15/8 = 2 - 1/8

and so on; the nth finite sum is 2 - 1/2^n. This converges to 2 as n goes to infinity, so 2 is the value of the infinite sum.

8 0
3 years ago
(2x² - 5) - (3x² + 4).
Goshia [24]

(2x² - 5) - (3x² + 4).

Pretend that there is a -1 in front of :(3x² + 4).

(2x^2-5)-1(3x^2+4)

2x^2-5-3x^-4

2x^2-3x^2-5-4

=-x^2-9

Answer: -x^2-9

3 0
3 years ago
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