Y=(kx)/z
15=(k10)/4
15=(5k/2)
15=k(5/2)
ties both sides by 2/5 to clear fraction
6=k
y=(6x)/z
x=20
z=6
y=(6*20)/6
y=20
If (y-1) is a factor of f(y), f(y)=0 when y=1. So if you find that f(1)=0, then (y-1) is a factor of f(y).
f(y)=y^3-9y^2+10y+5
f(1)=1-9+10+5=7
Since f(1)=7, (y-1) is not a factor.
Answer:
length of BC = 5 1/4 feet
Step-by-step explanation:
Area of a triangle = 1/2×base×height
Area = 4 3/8 square feet
Base = AC= 1 2/3 feet
Height = BC = ?
Area of a triangle = 1/2×base×height
4 3/8 = 1/2 × 1 2/3 × height
35/8 = 1/2 × 5/3 × height
35/8 = 5/6 × height
Height = 35/8 ÷ 5/6
= 35/8 × 6/5
= (35 × 6) / (8 × 5)
= 210 / 40
= 5 1/4 feet
Height = BC = 5 1/4 feet
length of BC = 5 1/4 feet
Answer:
C. True; by the Invertible Matrix Theorem if the equation Ax=0 has only the trivial solution, then the matrix is invertible. Thus, A must also be row equivalent to the n x n identity matrix.
Step-by-step explanation:
The Invertible matrix Theorem is a Theorem which gives a list of equivalent conditions for an n X n matrix to have an inverse. For the sake of this question, we would look at only the conditions needed to answer the question.
- There is an n×n matrix C such that CA=
. - There is an n×n matrix D such that AD=
. - The equation Ax=0 has only the trivial solution x=0.
- A is row-equivalent to the n×n identity matrix
. - For each column vector b in
, the equation Ax=b has a unique solution. - The columns of A span
.
Therefore the statement:
If there is an n X n matrix D such that AD=I, then there is also an n X n matrix C such that CA = I is true by the conditions for invertibility of matrix:
- The equation Ax=0 has only the trivial solution x=0.
- A is row-equivalent to the n×n identity matrix
.
The correct option is C.