<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
C. 4.2a + 0.8
Step-by-step explanation:
Given:
The two binomials given for addition are:
and 
Now, adding both the binomials, we get:
Distributing the positive sign inside the second binomial, we get:
Now, combining like terms using the commutative property of addition, we get:
Simplifying the above expression, we get:
Therefore, the resulting addition of the given binomials is 
Hence, option C is the correct answer.
Answer: B aka (3’2) + (3’2)
Step-by-step explanation:
I got it right on Edge 2021, good luck! Also if right, can you please mark Brainliest?
Answer:
40
Step-by-step explanation:
75% divided by 3 since its 3/4 of 100
do the same to 30
