$y=2x\\y=x^2-15\\\\x^2-15=2x\\x^2-2x-15=0\\x^2-5x+3x-15=0\\x(x-5)+3(x-5)=0\\(x+3)(x-5)=0\\x=-3 \vee x=5\\\\y=2\cdot(-3) \vee y=2\cdot5\\y=-6 \vee y=10\\\\(x,y)\in\{(-3,-6),(5,10)\}$

7 0

3 years ago

ZA and B are supplementary angles. If m A = (2x – 14) and m

Elena-2011 [213]

Answer:

∡ZA = 66°

Step-by-step explanation:

Suplementary angles sum 180°

ZA + ZB = 180°

then:

(2x - 14)° + (3x-6)° = 180°

2x + 3x - 14 - 6 = 180

5x - 20 = 180

5x = 180 + 20

5x = 200

x = 200/5

x = 40

then:

∡ZA = (2x - 14)

∡ZA = (2*40 - 14)

∡ZA = (80-14)

∡ZA = 66°

7 0

3 years ago

I would like to know if I am solving correctly so far and what I do after this to continue solving.

12345 [234]

$\bf A=\cfrac{13\cdot 3\sqrt{3}}{2}\implies A=\cfrac{39\sqrt{3}}{2}$

4 0

3 years ago