Answer:
A. (0, 1) and (2, -2)
B. Slope (m) = -³/2
C. y + 2 = -³/2(x - 2)
D. 
E. 
Step-by-step explanation:
A. Two points on the line from the graph are: (0, 1) and (2, -2)
B. The slope can be calculated using two points, (0, 1) and (2, -2):
Slope (m) = -³/2
C. Equation in point-slope form is represented as y - b = m(x - a). Where,
(a, b) = any point on the graph.
m = slope.
Substitute (a, b) = (2, -2), and m = -³/2 into the point-slope equation, y - b = m(x - a).
Thus:
y - (-2) = -³/2(x - 2)
y + 2 = -³/2(x - 2)
D. Equation in slope-intercept form, can be written as y = mx + b.
Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.
y + 2 = -³/2(x - 2)
2(y + 2) = -3(x - 2)
2y + 4 = -3x + 6
2y = -3x + 6 - 4
2y = -3x + 2
y = -3x/2 + 2/2
E. Convert the equation in (D) to standard form:
The domain is 14^4 and the answer is23^
<span>There are two approaches to translate this inquiry, to be specific:
You need to know a number which can go about as the ideal square root and also the ideal block root.
You need to know a number which is an ideal square and in addition an ideal 3D shape of a whole number.
In the primary case, the arrangement is straightforward. Any non-negative whole number is an ideal square root and in addition a flawless solid shape foundation of a bigger number.
A non-negative whole number, say 0, is the ideal square foundation of 0 and additionally an immaculate shape base of 0. This remains constant for all non-negative numbers starting from 0 i.e. 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
In the second case as well, the arrangement is straightforward however it involves a more legitimate approach than the primary choice.
A flawless square is a number which contains prime variables having powers which are a different of 2. So also, a flawless block is a number which includes prime variables having powers which are a numerous of 3.
Any number which includes prime components having powers which are a various of 6 will be the answer for your inquiry; a case of which would be 64 which is the ideal square of 8 and an ideal 3D shape of 4. For this situation, the number 64 can be spoken to as prime variables (i.e. 2^6) having powers (i.e. 6) which are a different of 6.</span>
