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2 years ago

Guys help don't have enough time left. This can really effect everything if this is correct so try your best.

Mathematics

2 answers:

Gekata [30.6K]2 years ago

3 0

Answer: 180

Step-by-step explanation:

azamat2 years ago

3 0

Answer: 180ft^3

Step-by-step explanation:

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89% of what number is 14

MariettaO [177]

Answer:

D: 14 = 0.89 x n; 15.7

Step-by-step explanation:

To get 89% of a number you have to multiply that number by 0.89

8 0

3 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

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2 years ago

The bicycle repair shop charged Devontae $34

vova2212 [387]

Answer: $42.4 dollars

Step-by-step explanation: PLZ PLZ PLZ MARK BRAINLIEST

4 0

3 years ago

Combine the like terms to create an equivalent expression: \large{-k-(-8k)}−k−(−8k)minus, k, minus, (, minus, 8, k, )

PIT_PIT [208]

Answer:

Step-by-step explanation:

The given expression is

$-k-(-8k)$

We need to find the simplified form of the given expression.

Like terms: The terms which have same variables of same degree and known as like terms. For example: 2x and 4x are like terms.

The given expression can be rewritten as

$-k+8k$

On combining like terms we get

$(-1+8)k$

$7k$

Therefore, the equivalent expression of the given expression is 7k.

3 0

3 years ago

*Will mark brainest!* Determine whether the guven equations are parallel, perpendicular or neither.

ioda

These are parallel lines

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2 years ago