Answer:
<h2> Assuming your friend said the temperature over there was 68 degrees Fahrenheit in degrees C it would be 20 °C</h2>
Step-by-step explanation:
The question is not complete, as the information, your best friend in Europe about the temperature over there is missing, nevertheless, we can proceed with this problem by plugging in an assumed temperature.
The expression for conversion from degrees F to degrees C is given as
T(°C) = (T(°F) - 32) × 5/9
Now say temperature your friend e-mailed you is 68 degrees Fahrenheit (you can as well plug in your own value)
T(°C) = (68°F - 32) × 5/9
T(°C) = (36) × 5/9
T(°C) = 180/9 = 20 °C
T(°C) = 20 °C
The value of

,

, and

for each schools is given in the first picture below.

is the lower quartile

is the median

is the upper quartile
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
Answer:
120°
Step-by-step explanation:
Add the 2 opposite angles to find the exterior angle.
50° + 70° = 120°
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-Chetan K