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Hunter-Best [27]
3 years ago
7

If you quadratic equation has two complex roots and one of the roots is x+2i, what is the second root?

Mathematics
1 answer:
Tanzania [10]3 years ago
4 0

Answer:

x-2i

Step-by-step explanation:

Complex roots come in pairs, called complex conjugates

If you have a root a+bi, the other root is a-bi

Since you have one root x+2i,  the other root is x-2i

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53,656 is the answer.
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Find BC if AC = 13 and AB = 10
maxonik [38]

Answer:

BC=3

Step-by-step explanation:

<em>We </em><em>can </em><em>solve </em><em>this </em><em>by </em><em>eliminating</em><em> </em><em>given </em><em>detail </em><em>of </em><em>A.</em>

AC=13 , AB=10

<u>To </u><u>find </u><u>BC,</u><u> </u><u>We </u><u>minus </u><u>A</u><u>C</u><u> </u><u>With </u><u>AB</u>

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7 0
3 years ago
Please help me for the brainliest answer
Oxana [17]

Answer:

aₙ= -2n²

Step-by-step explanation:

<h2><u>Solution 1:</u></h2>

The sequence:

  • -2, -8, -18, -32, -50

The difference between the terms:

  • -6, -10, -14, -18
  • a₁= -2
  • a₂= a₁ - 6 = a₁ - 2*3= a₁- 2*(2²-1)
  • a₃= a₂ - 10 = a₁ - 16= a₁ - 2*8= a₁ - 2*(3²-1)
  • a₄= a₃- 14= a₁ - 30= a₁ - 2*15= a₁ - 2*(4² -1)
  • ...
  • aₙ= a₁ -2*(n²-1)= -2 -2n² +2= -2n²

As per above, the nth term is: aₙ= -2n²

<h2><u /></h2><h2><u>Solution 2</u></h2>

The sequence:

  • -2, -8, -18, -32, -50
  • -2*1, -2*4, - 2*9, -2*25
  • -2*1², -2*2², -2*3², -2*4², -2*5², ..., -2*n²
  • aₙ= -2n²
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3 years ago
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