<u>Answer:</u>
The range of the function y = 2cos x is -2 <y < 2 .
<u>Step-by-step explanation:</u>
We know that cos (0) = 1 and cos (π) = - 1 are the two extreme values which cos x assume when x ∈ R and it is also that cos (x) is a continuous periodic function with period 2π when x ∈ R ,
since ,
cos (x + 2π) = cos x
So, the range of the function y = 2cos x is -2 <y < 2 .
Answer:
17.84
Step-by-step explanation:
2.23
8 x
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17.84
Answer:
3.95 and -3.95
Step-by-step explanation:
To graph a circle you can use the formula or (x – h)^2 + (y – k)^2 = r^2. So substituting in the given, we get x^2+y^2=49/pi. The x intercept is when y=0. So x^2=49/pi and so
x = sqrt(49/pi) and rounding to the nearest tenth, we get 3.95 and -3.95 because it isn’t a principal square root.
Answer:
D) -122
Step-by-step explanation:
Given:
We need to find f(-4).
Now by substituting the value of x =-4 in above equation we get;
By using PEDMAS we will solve for exponential function first we get;
Now we know that 
So we get;
Now using PEDMAS we will solve division.
Now using PEDMAS we solve multiplication.
Finally by subtraction we get;
