I will give brainlest!!! ❤️ True or false: a line segment has exactly one endpoint ?

Mathematics

1 answer:

Alex73 [517]3 years ago

6 0

Answer:

False

line segment has exactly two end point

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Find r(x + 1) if r(x) = x3 + x + 1

suter [353]

Substitute x + 1 as x in the equation of the function:

$r(x)=x^3+x+1\\\\r(x+1)=(x+1)^3+(x+1)+1=x^3+3(x^2)(1)+3(x)(1^2)+1^3+x+1+1\\\\=x^3+3x^2+3x+x+2=x^3+3x^2+4x+2$

Used

$(a+b)^3=a^3+3a^3b+3ab^3+b^3$

7 0

3 years ago

Read 2 more answers

Which is an exponential decay function f (x)=3/4 (7/4)x f (x)=2/3 (4/5)-x. F (x)=3/2 (8/7)-x f (x)=1/3 (9/2)x

dsp73

The given functions are
$1.\, f(x)= \frac{3}{4}( \frac{7}{4})^{x} \\ \\2.\,f(x)= \frac{2}{3}( \frac{4}{5} ) ^{-x}\\\\3.\, f(x)= \frac{3}{2} ( \frac{8}{7} )^{-x}\\\\4.\,f(x)= \frac{1}{3} ( \frac{9}{2} )^{x}$

Evaluate the functions.
1. Because 7/4 > 1 and the exponent is positive,
the function does not decay.
2.Because 4/5 < 1 and the exponent is negative,
the function does not decay.
3. Because 8/7 > 1 and the exponent is negative,
the function decays.
4. Because 9/2 > 1 and the exponent is positive,
the function does not decay.

A composite plot the functions verifies the answer.

Answer: $f(x)= \frac{3}{2} ( \frac{8}{7} )^{-x}$