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MAVERICK [17]
3 years ago
10

A cone has a radius of 5 ft and a height of 15 ft. It is empty and is being filled with water at a constant rate of 15 15 ft 3 f

t3 / sec sec . Find the rate of change of the radius of the surface of the water when the radius of the surface of the water is 2 2 ft. (You must also include the units)
Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

\frac{dr}{dt}=0.11062ft/sec

Step-by-step explanation:

From the question we are told that:

Radius r=5ft

Height H=15ft

Rate R=15ft/3sec =5ft/s

Surface Radius R_{surf}=2.2ft

Generally the equation for Volume is mathematically given by

 V=\frac{1}{3}\pi*r^2h

Since radius to height ratio gives

 \frac{r}{h}=\frac{5}{15}

 \frac{r}{h}=\frac{1}{3}

 h=3r

Therefore

 V=\frac{1}{3}\pi*r^2(3r)

 V=\pi r^3

Generally the equation for Change of Volume is mathematically given by

 \frac{dv}{dt}=\pi \frac{d}{dt}(r^3)

 \frac{dv}{dt}=\pi 3*r^2 \frac{dr}{dt}

 \frac{dv}{dt}=\pi 3*(2.2)^2 \frac{dr}{dt}

 \frac{dr}{dt}=\frac{5}{45.62}

 \frac{dr}{dt}=0.11062ft/sec

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Answer:

-3

Step-by-step explanation:

since the 9 in negative you subtract 9 by 6 and you get 3 then you put the negative sign in front of the 3 making it -3

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0.1 x 23<br><br><br><br><br><br><br><br> Please help me
zhannawk [14.2K]

Answer:

the answer would be 2.3

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Line segment XY has the coordinates X(–12, –6) and Y(5, 6). What is the approximate length of line segment XY?
malfutka [58]

The approximate length of line segment XY is 20.8 units

<h3>How to calculate the distance between two points</h3>

The formula for calculating the distance between two points is expressed as:

A = √(x2-x1)²+(y2-y1)²

Given the coordinate points X(–12, –6) and Y(5, 6). The distance between them is expressed as;

XY = √(5+12)²+(6+6)²

XY = √(17)²+(12)²

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XY = 20.8

Hence the approximate length of line segment XY is 20.8 units

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6 0
2 years ago
What is the volume, in cubic ft, of a rectangular prism with a height of 3ft, a width of 8ft, and a length of 6ft?
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<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ volume = length x width x height

volume = 6 x 3 x 8

volume = 144 cubic ft

➶ Hope This Helps You!

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The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
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