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Tems11 [23]
3 years ago
5

Can someone please please please help me it’s ergent

Mathematics
2 answers:
JulsSmile [24]3 years ago
7 0

Answer:

D 192

Step-by-step explanation:

used:  new: total

4:          1     :  5

We have 240 stamps

240/5 = 48

Multiply each number by 48

used:  new: total

4*48:   1*48  :  5*48

192  :  48     :  240

There are 192 used stamps and 48 new stamps in his collections

yuradex [85]3 years ago
4 0

Answer:

192 used stamps.

Step-by-step explanation:

Since the ratio is 4 used stamps for every new stamp, you can count that as 5 stamps total. Then divide 240 by 5 to get 48. Then multiply that by 4 to get 192.

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Which inequality is represented in the number line below?-5-4-3-2-1 0 1 2 3 4 5OA.-7+2<22+3<4+2OB.-9≤-3x-6≤6OC.-6 ≤ x + 2
S_A_V [24]

The Solution:

The correct answer is [option B]

Given:

Required:

To determine the inequality represented by the given number line.

7 0
11 months ago
Can someone help me with these questions?
Elina [12.6K]
1) 1, -2..for the first question
4 0
2 years ago
Kara has 21 collectible buttons to sell. She sells the small buttons for $3 and the large buttons for $4, and earns a total of $
Serga [27]
We know that there are 21 buttons total. x is the number of small buttons and y is the number of large buttons. 

Therefore, our first equation should be x+y = 21.

We know the small buttons sell for 3 dollars, meaning 3x represents how much is made from the small buttons. The larger buttons sell for 4 dollars, meaning 4y is how much is made from the large buttons. 

We also know that the total of the buttons sold is 68 dollars. Therefore 3x + 4y = 68 is our second equation.

From this information, the answer is the first set.

5 0
3 years ago
Tyler wears a jacket to school every 3rd day and a scarf to school every 8th day. What will be the first day Tyler will wear his
disa [49]

Answer:

24th day will  be the first day on which Tyler will wear his jackets and scarf to school

Step-by-step explanation:

We can find the first day on which the Tyler will wear his jackets and scarf to school by taking the LCM of(3,8)

<u>Finding the LCM of(3,8)</u>

List all prime factors for each number.

Prime Factorisation of 3 shows:

3 is prime  =>  3^1

Prime Factorisation of 8 is:

2 x 2 x 2  =>  2^3

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new super-set list is

2, 2, 2, 3

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 2 x 3 = 24

6 0
3 years ago
How come this person didn’t divide EVERYTHING on the left by 2? I thought you had to...
damaskus [11]

The short answer is that algebra doesn't work that way. You wouldn't divide *everything* by 2, but every term that contains a factor of 2.

In the expression

2 (6<em>x</em> - 1) + 2 (2<em>x</em> + 5)

both terms have a factor of 2 (the 2 out in front of them). They're the ones that get canceled when dividing by 2:

(2 (6<em>x</em> - 1) + 2 (2<em>x</em> + 5)) / 2 = 2/2 (6<em>x</em> - 1) + 2/2 (2<em>x</em> - 5)

… = 1 (6<em>x</em> - 1) + 1 (2<em>x</em> - 5)

… = (6<em>x</em> - 1) + (2<em>x</em> - 5)

and so on.

Looking ahead, it turns out that the equation is solved by <em>x</em> = 7. This makes 6<em>x</em> - 1 = 41 and 2<em>x</em> + 5 = 19. So the equation is saying that, if you make these replacements,

2×41 + 2×19 = 120

If you divide *everything* on the left by 2, you end up with fractions:

(2/2)×(41/2) + (2/2)×(19/2) = 41/2 + 19/2

but 41 + 19 = 60, so the end result would be 30, but that's not the same as 120/2 = 60.

5 0
2 years ago
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