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Lorico [155]
2 years ago
10

A certain family has a husband, wife, son, and daughter. All together they are 68 years old. The husband is 3 years older than t

he wife, and the son is 3 years older than the daughter. Four years ago, all together the family was 54 years old. How old is the husband now?
Mathematics
1 answer:
Vsevolod [243]2 years ago
5 0

Answer:

32 years old

Step-by-step explanation:

The husband is 32 years old as the wife is 3 years younger than the husband. The son is 3 years older than the daughter. Their family altogether total age today is 68 years while 4 years ago their age total was 54 years. The difference is 14 years. If we divide the difference into 4 then the age can not be whole number which means daughter is born after 2 years. She is now 2 years older. Son is 3 years older than the daughter which means he is 5 years old. The husband then must be 32 years old and wife is 3 years younger which means she is 29 years old now.

32 + 29 + 5 + 2 = 68 years.

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Answer:

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Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

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a)

P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108

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b) Note that P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2) . And

P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227

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