The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Answer:
x=0, yes.
Step-by-step explanation:
3x+8=5x+8
5x-3x+8=8
2x+8=8
2x=8-8
2x=0
x=0/2
x=0
Answer:
im scared for my future, I dont wanna learn about this, it looks hard
Step-by-step explanation:
Answer:
Y=-2/3x + 5
Step-by-step explanation:
Answer:
1 and 5. Can I get a brainliest???
Step-by-step explanation:
