GUI stands for "___ user interface."

Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv

elena-s [515]

Answer:

PART ONE

import java.util.Scanner;
public class CountToLimit {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int countLimit = 0;
int printVal = 0;
// Get user input
System.out.println("Enter Count Limit");
countLimit = scnr.nextInt();
do {
System.out.print(printVal + " ");
printVal = printVal + 1;
} while ( printVal<=countLimit );
System.out.println("");
return;
}
}

PART TWO

import java.util.Scanner;
public class NumberPrompt {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
System.out.print("Your number < 100: ");
int userInput = scnr.nextInt();
do {
System.out.print("Your number < 100: ");
userInput = scnr.nextInt();
}while (userInput>=100);
System.out.println("Your number < 100 is: " + userInput);
return;
}
}

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10

7 0

3 years ago

Convert the decimal number 164 into the equivalent 8 bit binary number.

umka2103 [35]

Answer:

10100100

Explanation:

8 bit system consists of 8 bits or 8 positions and each of them can have binary value (0 or 1).

Each bit is equivalent to a certain power of number 2. Important to know is that you read these bits from right to left.

So, this means that the bit furthest to the right has the value of 2^0, which is 1. The bit to the left has the value of 2^1, which is 2. Next one is 2^2, which is 4 etc. This means that the bit furthest to the left has the value of 2^7, which is 128.

The bit has this potential value only if value 1 if is in its position. If the value is 0 then, regardless of position, value of the bit is 0.

Decimal value of the number is calculated when we add all the values of the bits marked with 1.

So, we're dealing with number 164. We already said that leftmost bit has the value of 128 if it's marked with 1:

1 0 0 0 0 0 0 0 = 128

Next bit has the value of 64, but 128+64 would exceed the value of our number, so the second leftmost bit remains 0.

Next bit has the value of 32, 128+32 is 160, which is less then our number, so we mark the third bit with 1:

1 0 1 0 0 0 0 0 = 160

Similarly, we continue down the line. We only need 4 to reach the value of our number, so we'll mark with 1 the bit that has the value of 4, which leaves us with the solution:

1 0 1 0 0 1 0 0 = 164

7 0

3 years ago

Question 1 (True/False Worth 3 points)

ANTONII [103]

False because the internet connects with multiple communication networks to exchange information

6 0

2 years ago

This network passes data most of the time, but sometimes for reasons unknown to the junior network engineer in charge of monitor

Kaylis [27]

Answer:

The characteristic that is violated is Availability.

Explanation:

The network is passing data at mostly, it means performance is good. Junior network engineer is doing his job well then there is minimum chance of network failure or lack of manageability.
The scalability; range of computing capabilties can be managed by the engineer.
However, sometimes the core router might get crashed due to unavailability of the network that is not under the control of the engineer.

8 0

3 years ago

Which of the following lines correctly defines a String variable

lidiya [134]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is C i.e. String s = "apluse";

The rule or syntax of declaring string in any programming language is given below:

String variable-name = "yourString";

For declaring string variable, first, you write "String" that is a keyword of a programming languages for declaring string variables, such as int before the variable name for declaring integer variable. Then, you need to write a meaningful name of the string as a variable. After string variable name, you need to put the equal operator and then write the string in double quotation("") marks and after that put the instruction terminator that is ";".

So, according to this syntax, option C is correct.

While other options are not correct because:

In option a, string is not encapsulated in double quotation. Option B does not have varaible type such as String and Option E does not have variable name and its value also. So, only option C is correct and all other except C are incorrect.

3 0

3 years ago