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makvit [3.9K]
3 years ago
5

Look at the following figure. Copy the cross onto another piece of paper. Then, cut apart the four pieces labeled A, B, C, and D

. You now have a jigsaw puzzle with four pieces. Can you figure out how to put the pieces back together to form a square?

Mathematics
1 answer:
kozerog [31]3 years ago
3 0

Answer:

C should slot on top of A.

Then D should slot in next to C of the left.

Lastly B should be beneath D and on the left of A.

Hope that makes sense.

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5004300 standard form
IRINA_888 [86]

Answer:

Five million four thousand three hundred

Step-by-step explanation:

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3 years ago
Please help ASAP thank you
horrorfan [7]

Step-by-step explanation:

5/8-7/8=2/8 so that is the height

the width is 1/2

and the length is 3/8

you have too multiply 1/2 and 3/8 which is 3/16.

hope this is correct and helps u out

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3 years ago
1. Explain the difference between circumscribed angles and inscribed angles in relationship to a circle.
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9514 1404 393

Explanation:

1. Consider the attachment. Angle CDF is a circumscribed angle. It is formed at the intersection of two tangents to the circle. Angles BCE, CBE, and BEC are inscribed angles. Their vertices are on the circle, and they are formed by two chords.

If a chord degenerates to zero length, the ray it represents with respect to an inscribed angle becomes a tangent. That is, angles BCD and ECD can also be considered to be inscribed angles. Similarly, straight angle DFG at tangent point F can be considered to be a degenerate case of both an inscribed angle and a circumscribed angle. (Some authors may not include degenerate cases in their definitions. YMMV)

__

2. The <em>general form</em> of the equation of a circle is ...

  Ax² +Ay² +Dx +Ey +F = 0

Any equation of a circle can be put in this form. If we divide by A, this can be written as ...

  x² +y² -2hx -2ky +c = 0 . . . . where h = -D/(2A), k = -E/(2A), c = F/A

and the equation can be further transformed to the <em>standard form</em> ...

  (x -h)² +(y -k)² = r² . . . . . where r² = h² +k² -c

The last equation is the result of "completing the square" by adding h² and k² to both sides of the second equation shown. The values of h and k are as shown above, given the coefficients of the general form equation.

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3. Again refer to the attached diagram.

a) a radius is a line segment with the circle center at one end and a point on the circle at the other end. AB and AC are radii.

b) A diameter is a line segment whose ends are on the circle and whose midpoint is the center of the circle. BC is a diameter.

c) A chord is a line segment whose end points lie on the circle. BC, BE, and CE are chords.

d) A secant is a line containing two points of the circle. Lines CG and CE are secants.

e) A tangent is a degenerate case of a secant in which the two points of intersection merge to one point of intersection. It is a line that touches the circle at exactly one point, the point of tangency. DG and DC are tangents.

f) The point of tangency is the single point where a tangent intersects a circle. A radius to the point of tangency (such as AC) is always perpendicular to the tangent line (DC).

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What is the height of the cilender if the volume is 904.78 and the radius is 6^2?
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What units is it in exactly?
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Step-by-step explanation:

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