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nika2105 [10]
3 years ago
15

1. Explain the difference between circumscribed angles and inscribed angles in relationship to a circle.

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
7 0

9514 1404 393

Explanation:

1. Consider the attachment. Angle CDF is a circumscribed angle. It is formed at the intersection of two tangents to the circle. Angles BCE, CBE, and BEC are inscribed angles. Their vertices are on the circle, and they are formed by two chords.

If a chord degenerates to zero length, the ray it represents with respect to an inscribed angle becomes a tangent. That is, angles BCD and ECD can also be considered to be inscribed angles. Similarly, straight angle DFG at tangent point F can be considered to be a degenerate case of both an inscribed angle and a circumscribed angle. (Some authors may not include degenerate cases in their definitions. YMMV)

__

2. The <em>general form</em> of the equation of a circle is ...

  Ax² +Ay² +Dx +Ey +F = 0

Any equation of a circle can be put in this form. If we divide by A, this can be written as ...

  x² +y² -2hx -2ky +c = 0 . . . . where h = -D/(2A), k = -E/(2A), c = F/A

and the equation can be further transformed to the <em>standard form</em> ...

  (x -h)² +(y -k)² = r² . . . . . where r² = h² +k² -c

The last equation is the result of "completing the square" by adding h² and k² to both sides of the second equation shown. The values of h and k are as shown above, given the coefficients of the general form equation.

__

3. Again refer to the attached diagram.

a) a radius is a line segment with the circle center at one end and a point on the circle at the other end. AB and AC are radii.

b) A diameter is a line segment whose ends are on the circle and whose midpoint is the center of the circle. BC is a diameter.

c) A chord is a line segment whose end points lie on the circle. BC, BE, and CE are chords.

d) A secant is a line containing two points of the circle. Lines CG and CE are secants.

e) A tangent is a degenerate case of a secant in which the two points of intersection merge to one point of intersection. It is a line that touches the circle at exactly one point, the point of tangency. DG and DC are tangents.

f) The point of tangency is the single point where a tangent intersects a circle. A radius to the point of tangency (such as AC) is always perpendicular to the tangent line (DC).

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The Midpoint of AB dkdldl
Nutka1998 [239]
  • The Midpoint of AB is (1,0).

Given that:

  • In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).

To find:

  • The Midpoint of line AB.

So, according the question

We know that,

The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M ( \frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} ).

Now from question,

We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.

So, we can say that

   A is (3,1) or x₁ = 3 and y₁ = 1.

   B (-1,-1) or x₂ = -1 and y₂ = -1.

∵ The coordinates of midpoint M (X,Y)

          X = \frac{x_1 + x_2}{2}

              = \frac{3-1}{2}

              = 2/2

          X = 1.

And

          Y = \frac{y_1 + y_2}{2}

              = \frac{1-1}{2}

              = 0/2

          Y = 0.

So, the midpoint of line AB is M (1,0)

To learn more about Midpoint of line, please click on the link;

brainly.com/question/14687140

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8 0
1 year ago
Tom bought 7 new baseball trading cards to add to his collection the next day his dog ate half of his collection. There are now
Ede4ka [16]

Answer: 83 cards

Step-by-step explanation:

38 x 2 + 7 = 83

6 0
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What is the length of segment AB? (4 points)
Sveta_85 [38]

Answer:

10 units

Step-by-step explanation:

\sqrt{(0-6)^{2} +(10-2)^{2} }\\\\\sqrt{(-6)^{2}+(8)^{2} } \\\\\sqrt{36+64}\\\\\sqrt{100}\\\\10

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3 years ago
Which number produces a rational number when added to 0.53
NARA [144]

Answer:

5/7 or D

Step-by-step explanation:

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6 0
1 year ago
3. A table has a length of 3.4 meters and a width of 1.5 meters. Mang Jose painted the to portion approximately 3.75 m². What wa
sergij07 [2.7K]

Answer:

#3

<u>What was the area left unpainted?</u>

  • 3.4*1.5 - 3.75 = 1.35 m²

Option D

#4

<u>How big is Ben's share?</u>

  • 998.50 - 18.6² = 652.54 m²

Option A

#5

<u>The area of a circular pool whose radius is 2 m:</u>

  • A = π² = 3.14*2² = 12.56 m²

Option A

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