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nika2105 [10]
3 years ago
15

1. Explain the difference between circumscribed angles and inscribed angles in relationship to a circle.

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
7 0

9514 1404 393

Explanation:

1. Consider the attachment. Angle CDF is a circumscribed angle. It is formed at the intersection of two tangents to the circle. Angles BCE, CBE, and BEC are inscribed angles. Their vertices are on the circle, and they are formed by two chords.

If a chord degenerates to zero length, the ray it represents with respect to an inscribed angle becomes a tangent. That is, angles BCD and ECD can also be considered to be inscribed angles. Similarly, straight angle DFG at tangent point F can be considered to be a degenerate case of both an inscribed angle and a circumscribed angle. (Some authors may not include degenerate cases in their definitions. YMMV)

__

2. The <em>general form</em> of the equation of a circle is ...

  Ax² +Ay² +Dx +Ey +F = 0

Any equation of a circle can be put in this form. If we divide by A, this can be written as ...

  x² +y² -2hx -2ky +c = 0 . . . . where h = -D/(2A), k = -E/(2A), c = F/A

and the equation can be further transformed to the <em>standard form</em> ...

  (x -h)² +(y -k)² = r² . . . . . where r² = h² +k² -c

The last equation is the result of "completing the square" by adding h² and k² to both sides of the second equation shown. The values of h and k are as shown above, given the coefficients of the general form equation.

__

3. Again refer to the attached diagram.

a) a radius is a line segment with the circle center at one end and a point on the circle at the other end. AB and AC are radii.

b) A diameter is a line segment whose ends are on the circle and whose midpoint is the center of the circle. BC is a diameter.

c) A chord is a line segment whose end points lie on the circle. BC, BE, and CE are chords.

d) A secant is a line containing two points of the circle. Lines CG and CE are secants.

e) A tangent is a degenerate case of a secant in which the two points of intersection merge to one point of intersection. It is a line that touches the circle at exactly one point, the point of tangency. DG and DC are tangents.

f) The point of tangency is the single point where a tangent intersects a circle. A radius to the point of tangency (such as AC) is always perpendicular to the tangent line (DC).

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Help subtract (xsquared +43x10)-(10xsquared-5x+10 express the answer in standard form
ad-work [718]

Answer:

\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}

Step-by-step explanation:

(x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x

6 0
4 years ago
In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
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Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

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3 years ago
Put the following numbers in order from smallest to largest.
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Step-by-step explanation:

the order in which you asked the question is correct

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What is the answer to - 5y = - 5 and. 7x +6y=7
Vikentia [17]

Answer:

(1/7, 1)

Step-by-step explanation:

By "answer," you probably meant "solution."  What is the "solution of the system of linear equations

- 5y = - 5

+ 7x +6y=7

The first eqation can be solved for y:  y = 1.  Substitute 1 for y in the secon equation.  Then 7x + 6(1) = 7, or 7x = 1, or x = 1/7.

The solution to this system is (1/7, 1)

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