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nika2105 [10]
3 years ago
15

1. Explain the difference between circumscribed angles and inscribed angles in relationship to a circle.

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
7 0

9514 1404 393

Explanation:

1. Consider the attachment. Angle CDF is a circumscribed angle. It is formed at the intersection of two tangents to the circle. Angles BCE, CBE, and BEC are inscribed angles. Their vertices are on the circle, and they are formed by two chords.

If a chord degenerates to zero length, the ray it represents with respect to an inscribed angle becomes a tangent. That is, angles BCD and ECD can also be considered to be inscribed angles. Similarly, straight angle DFG at tangent point F can be considered to be a degenerate case of both an inscribed angle and a circumscribed angle. (Some authors may not include degenerate cases in their definitions. YMMV)

__

2. The <em>general form</em> of the equation of a circle is ...

  Ax² +Ay² +Dx +Ey +F = 0

Any equation of a circle can be put in this form. If we divide by A, this can be written as ...

  x² +y² -2hx -2ky +c = 0 . . . . where h = -D/(2A), k = -E/(2A), c = F/A

and the equation can be further transformed to the <em>standard form</em> ...

  (x -h)² +(y -k)² = r² . . . . . where r² = h² +k² -c

The last equation is the result of "completing the square" by adding h² and k² to both sides of the second equation shown. The values of h and k are as shown above, given the coefficients of the general form equation.

__

3. Again refer to the attached diagram.

a) a radius is a line segment with the circle center at one end and a point on the circle at the other end. AB and AC are radii.

b) A diameter is a line segment whose ends are on the circle and whose midpoint is the center of the circle. BC is a diameter.

c) A chord is a line segment whose end points lie on the circle. BC, BE, and CE are chords.

d) A secant is a line containing two points of the circle. Lines CG and CE are secants.

e) A tangent is a degenerate case of a secant in which the two points of intersection merge to one point of intersection. It is a line that touches the circle at exactly one point, the point of tangency. DG and DC are tangents.

f) The point of tangency is the single point where a tangent intersects a circle. A radius to the point of tangency (such as AC) is always perpendicular to the tangent line (DC).

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93000000 in standard form
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It’s already in standard form: 93,000,000

If we would put it in scientific notation though, it would be: 9.3 x10 ^7 (to the power of 7)
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3 years ago
I need help with this <br> ASAP!!!!!!!!!
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Answer:

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6 0
4 years ago
Arthur has decided to start saving for a new computer. His money is currently in a piggy bank at home, modeled by the function s
Leya [2.2K]

Two or more independent functions (say f(x) and g(x)) can be combined to generate a new function (say g(x)) using any of the following approach.

h(x) = f(x) + g(x)         h(x) = f(x) - g(x)

h(x) = \frac{f(x)}{g(x)}                   h(x) = f(g(x))

And many more.

The approach or formula to use depends on the question.

In this case, the combined function is:

f(x) = 75+ 10x

The savings function is given as

s(x) = 85

The allowance function is given as:

a(x) = 10(x - 1)

The new function that combined his savings and his allowances is calculated as:

f(x) = s(x) + a(x)

Substitute values for s(x) and a(x)

f(x) = 85 + 10(x - 1)

Open bracket

f(x) = 85 + 10x - 10

Collect like terms

f(x) = 85  - 10+ 10x

f(x) = 75+ 10x

Read more about functions at:

brainly.com/question/15458447

4 0
3 years ago
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Suppose that c is the center of a circle with radius 13 in and a point p is at a distance of 32 in from
pantera1 [17]
The sine of 1/2 the angle = 13 / 32

so this angle =  23.9695 degrees

Therefore the required angle = 2 * 23.9695  =  47.939  to 3 DP's. 

3 0
3 years ago
"We know that central angles are congruent, because it is given. We can say that segments AO, CO, BO, and DO are congruent becau
tangare [24]

Answer:

Refer below.

Step-by-step explanation:

We know that central angles are congruent, because it is given. We can say that segments AO, CO, BO, and DO are congruent because ALL RADII OF CIRCLE ARE CONGRUENT. Then by the SAS congruency theorem, we know that triangle AOC is congruent to triangle BOD. Finally, we can conclude that chord AC is congruent to chord BD because:"

CPCTC

4 0
4 years ago
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