5004300 standard form

Give the degree and classify the polynomial by the number of terms- 3

Alexxx [7]

The degree of the polynomial is found by looking at the term with the highest exponent on its variable(s). Examples: 5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial. 3x4+4x2The highest exponent is the 4 so this is a 4thdegree binomial.

4 0

2 years ago

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Two consecutive even integers have the following property. When the smaller integer is added to three times the larger integer,

polet [3.4K]

let x be the first integer
x+ 2 the second integer ( two consecutive even )

smaller integer added to three times the larger x + 3 ( x+2)
 two less than five times the smaller 5x - 2

x + 3 ( x+2) = 5x - 2

x+3x +6 = 5x -2

x=8
the first integer = 8
the second is x+2 =10

4 0

2 years ago

My friends last question pls answer ASAP

Dafna11 [192]

Answer:

64

Step-by-step explanation:

just count the blocks!

6 0

2 years ago

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Below are three different hypothesis tests about population proportions. For each test, use StatKey and the information given to

Ilia_Sergeevich [38]

Answer:

1a) p-hat=0.38

1b) P=0.08

1c) The null hypothesis is not rejected

2a) p-hat=0.64

2b) P=0.0027

2c) The null hypothesis is rejected

3a) p-hat=0.55

3b) P=0.153

3c) The null hypothesis is not rejected

Step-by-step explanation:

(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.

1a) The p-hat is p-hat=38/100=0.38.

1b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.3*0.7}{100}}=0.046$

The sample size is n=100.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.38-0.3}{0.046}=\frac{0.08}{0.046}= 1.74$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

1c) The null hypothesis is not rejected.

(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.

2a) The p-hat is p-hat=320/500=0.64.

2b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7*0.3}{500}}=0.02$

The sample size is n=500.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.64-0.7}{0.02}=\frac{-0.06}{0.02}=-3$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.

2a) The p-hat is p-hat=110/200=0.55.

2b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6*0.4}{200}}=0.035$

The sample size is n=200.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

2c) The null hypothesis is not rejected.

8 0

3 years ago

The cost C of moving rubble is proportional to the product of the mass M of the rubble and the distance D the rubble must be mov

Mandarinka [93]

Answer:

a) $C(M,D) = KMD$

b) $12,000

Step-by-step explanation:

We are given the following information in the question:

The cost C of moving rubble is proportional to the product of the mass M of the rubble and the distance D the rubble must be moved.

This can be written as:

a)

$C \propto M\times D\\C = KMD,\\\text{where K is the constant of proportionality.}$

$C(M,D) = KMD$

b) It costs 50 dollars to move 1 ton of rubble 1 mile

$50 = K\times 1\times 1\\\Rightarrow K= 50$

We have to find cost to move 16 tons 15 miles.

Putting the values in the function:

$C(16,15) = 50\times 16\times 15 = 12000$

Thus, $12,00 is the cost to move 16 tons 15 miles.

3 0

2 years ago