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Nataliya [291]
4 years ago
11

5x

{ { = 45}^{?} }^{2} " alt="5x { { = 45}^{?} }^{2} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Ilia_Sergeevich [38]4 years ago
8 0
\bf 5x=45^2\implies x=\cfrac{45^2}{5}\implies x=\cfrac{2025}{5}\implies x=405
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Anyone know the answer?
yan [13]

Answer:

0.

Step-by-step explanation:

The angle whose sine is 5/12 = 22.62 degrees and in Quadrant II it is

180 - 22.62 degrees

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givi [52]

Answer:

The value is V(x) =  1706.7 \pi

Step-by-step explanation:

From the question we are told that

The first equation is y=16\sqrt{x}

The second equation is y=4x

Generally the first point of intersection of the first and second equation is x = 0

Generally the obtain the second point of intersection of the two equation we equate the two equations

So

=> 16\sqrt{x} = 4x

=> \sqrt{x} = \frac{4x}{16}

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Generally the from washer method we have

V(x) =  \int\limits^4_0 {\pi [(H(x))^2 - (G(x))^2]} \, dx

So

H(x) =  16\sqrt{x}

and

G(x) =  4x

So

V(x) =  \int\limits^4_0 {\pi [(16\sqrt{x})^2 - (4x)^2]} \, dx

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=>V(x) =  \pi [256 \frac{x^2}{2} - 16 \frac{x^3}{3} ]|\left 4} \atop 0}} \right.

=> V(x) =  \pi [256 * \frac{ 4^2}{2}  - 16 * \frac{4^3}{3} ]

=> V(x) =  1706.7 \pi

6 0
3 years ago
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