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Butoxors [25]
3 years ago
9

What is the solution to this equation? 5x + 15 + 2x = 24 + 4x

Mathematics
2 answers:
pentagon [3]3 years ago
6 0

5

x

+

15

+

2

x

=

24

+

4

x

Add

5

x

and

2

x

.

7

x

+

15

=

24

+

4

x

Move all terms containing

x

to the left side of the equation.

3

x

+

15

=

24

Move all terms not containing

x

to the right side of the equation.

3

x

=

9

Divide each term by

3

and simplify.

x

=

3

Firdavs [7]3 years ago
4 0

To solve this equation, we must get all of the variables to one side of the equation and all of the constants (numbers) to the other side of the equation. To begin, however, we must add together the two terms on the left side of the equation that both have variables.

5x + 15 + 2x = 24 + 4x

7x + 15 = 24 + 4x

Next, we should subtract 4x from both sides of the equation so that the 4x on the right side cancels out and all of the variable terms are now on the left side.

3x + 15 = 24

Similarly, we also want to subtract 15 from both sides of the equation so that all of the constants are on the right side of the equation and we can get the variable alone on the left side.

3x = 9

Finally, we should divide both sides of the equation by 3 so that we can get rid of the coefficient of 3 on the variable x and get our answer.

x = 3

Therefore, your answer is x = 3.

Hope this helps!

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x=8

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Y=-155. Put in a table of 3 rows.
Alja [10]

Answer:

51.6666666667

Step-by-step explanation:

4 0
3 years ago
What is 1,015/12 as a mixed number and in simplest form?
ddd [48]
It would be 84 and 7/12
3 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
PLEASE HELP <br><br> y/7=x<br> what is y?
AlekseyPX

Answer:

You can't find y in this way

Step-by-step explanation:

You should know the value of x

But you can say

Y=7x

5 0
2 years ago
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