Answer:
0.97
Step-by-step explanation:
Given that a homeowner has two smoke detector alarms installed, one in the dining room (adjacent to the kitchen) and one in an upstairs bedroom (above the kitchen). If cooking produces smoke in the kitchen, the probability of setting off the dining room alarm (D) is .95. The probability of setting off the bedroom alarm (B) is .40.
Both alarms are independent of each other.
Probability for smoke detection=P(any one alarm rings)
=P(Kitchen alarm sets off)+P(bed room alarm sets off)-P(Both sets off)
Since both are independent
P(Both) = 
Probability for smoke detection
= 0.95+0.40-0.38
=0.97
29 students have to be in the class. If 29 students each pay 2.75, they will raise up 79.75 dollars! :)
Answer:
ok fking fk it ill just tell you, the most affordable way is doing it as a 4*3 package, the length will be 16, width 12, and the height 5. the area will be 960in^3, and the SA will be 664 in^2
Step-by-step explanation:
Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
Answer:
$1,045.21
Step-by-step explanation:
