Let f(x)=x^2-16. Find f^1(x)

1 answer:

4 0

Assuming is the inverse of the expression.

as you'd know, we first off do a quick switcharoo on the variables, and then solve for "y", so, let's do so,

$\bf \stackrel{f(x)}{y}=x^2-16\qquad inverse\implies \boxed{x}=\boxed{y}^2-16
\\\\\\
x+16=y^2\implies \sqrt{x+16}=\stackrel{f^{-1}(x)}{y}$

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