use the quotient rule then after using it the first time use it again on your resulting equation, since you are looking for the second derivative
Answer:
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Step-by-step explanation:
To find the diameter, you use the formula: 2x. we use 2x because the radius is 2 times the diameter.
so, if the radius is 3,980, then we substitute that into the formula.
2(3,980)
this will give us 7960. the diameter is 7960 miles.
Yes. When solving a problem like this, multiply the base numbers normally, and add the exponents together.
If you need more help, comment below and I'd be happy to assist.
![\text{Volume}=129.87cm^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%3D129.87cm%5E3)
Explanation
Step 1
the density of an object is given by:
![\text{density}=\text{ }\frac{mass}{\text{volume}}](https://tex.z-dn.net/?f=%5Ctext%7Bdensity%7D%3D%5Ctext%7B%20%7D%5Cfrac%7Bmass%7D%7B%5Ctext%7Bvolume%7D%7D)
Step 2
let
![\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7Bdensity%7D%3D0.77%5Cfrac%7Bg%7D%7Bcm%5E3%7D%20%5C%5C%20%5Ctext%7Bmass%7D%3D%5Ctext%7B%20100%20g%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Step 3
replace,
![\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\ \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7Bdensity%7D%3D%5Ctext%7B%20%7D%5Cfrac%7Bmass%7D%7B%5Ctext%7Bvolume%7D%7D%20%5C%5C%200.77%5Cfrac%7Bg%7D%7Bcm%5E3%7D%3D%5Cfrac%7B100g%7D%7B%5Ctext%7Bvolume%7D%7D%20%5C%5C%20%5Ctext%7Bvolume%7D%5Ccdot0.77%5Cfrac%7Bg%7D%7Bcm%5E3%7D%3D%5Ctext%7B1%7D00%5Ctext%7B%20g%7D%20%5C%5C%20%20%5C%5C%20%5Ctext%7BVolume%7D%3D%5Cfrac%7B100%5Ctext%7B%20g%7D%7D%7B0.77%5Cfrac%7Bg%7D%7Bcm%5E3%7D%7D%20%5C%5C%20%5Ctext%7BVolume%7D%3D129.87cm%5E3%20%5Cend%7Bgathered%7D)
I hope this helps you