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Daniel [21]
3 years ago
7

A,B,C,D are 4 towns. B is 40 kilometeres due east of A. C is 30 kilometeres due north of A. D is 45 kilometeres due south of A.

Worko out the bearing B from C

Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

Step-by-step explanation:

The diagram illustrating the scenario is shown in the attached photo.

We would determine angle ACB by applying the tangent trigonometric ratio which is expressed as

Tan θ = opposite side/adjacent side

Taking angle ACB as the reference angle,

Tan C = 40/30 = 1.33

Angle ACB = tan^-1(1.33) = 53.1°

The bearing is calculated with respect to the northern direction. Therefore, the bearing of B from C is

180 - 53.1 = 126.9°

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Answer
Length: 12 feet Width:4
Explanation
To get the area of a rectangle you times the length by the width
It says the length of the wall is 4 feet longer than TWICE it’s width since 12 times 4 is 48 and 12 is twice the amount of 4 plus 4 feet it fits the requirements of this question
3 0
3 years ago
juan needs to measure 6 cups of flour for a recipe.he only has a 1/4 cup measuring cup.how many times must he fill the measuring
Luba_88 [7]

Answer:

Juan would need to fill up the 1/4 measuring cup 24 times.

Step-by-step explanation:

So to measure one cup of flour with a 1/4 measuring cup, you would need to fill up the 1/4 measuring cup 4 times. Since we want 6 cups, you would need to fill up the 1/4 measuring cup 24 times. 6 times 4 = 24. Hope this helps!

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3 years ago
6x-1=2 (2×-3) solve for x
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8 0
3 years ago
1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
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Arturiano [62]

Answer:

the answer is 2

Step-by-step explanation:

(5×4-4×4)=2

6 0
3 years ago
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