A,B,C,D are 4 towns. B is 40 kilometeres due east of A. C is 30 kilometeres due north of A. D is 45 kilometeres due south of A.
Worko out the bearing B from C
1 answer:
Answer:
Step-by-step explanation:
The diagram illustrating the scenario is shown in the attached photo.
We would determine angle ACB by applying the tangent trigonometric ratio which is expressed as
Tan θ = opposite side/adjacent side
Taking angle ACB as the reference angle,
Tan C = 40/30 = 1.33
Angle ACB = tan^-1(1.33) = 53.1°
The bearing is calculated with respect to the northern direction. Therefore, the bearing of B from C is
180 - 53.1 = 126.9°
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Answer:
n = 6
Step-by-step explanation:
Answer:
221.87 feet
Step-by-step explanation:
Given that,
A 525 ft cable runs from the top of an antenna to the ground.
The angle of elevation made by the ground to the top of an antena 25°
We need to find the height of the antenna.
Using trigonometry,
Hypotenuse, H = 525 ft
θ = 25°
So,
So, the height of the antenna is equal to 221.87 feet.