A minimum because the function is positive. Positive quadratic functions always concave upwards (in a “bowl-like” shape), creating a curve/minimum at the bottom.
Answer:
356/7
Step-by-step explanation:
Upper Tolerance
Remark
The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.
Solution
<u>Upper Limit</u>

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

Which results in

With a final result for the fractions of 45/64
So the upper tolerance = 3 45/64
<u>Lower Tolerance</u>
Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

Your answer should be 3 and 43/64
Answer:
2
Step by step explanation:
Given: <u>The average mass of all the students in the class was 35.1 kg. After 1 student left the class, whose mass is 32.3kg, the average mass of the remaining students became 36.3kg, how many students were there in the class room now?</u>
Find out: <u>how many students were there in the class room after one student </u><u>left</u>
Solution: <u>Let the total number of remaining student be= n</u>
<u>Let the total number of remaining student be= nAnd the sum of mass of all the students be = x </u><u>kg</u>
So,

Make x the subject of formula

And





divide both side by n

N = 2.333
so total number of students remaining is 2
Answer:
<h2>
<em>f</em><em>(</em><em>5</em><em>)</em><em>=</em><em>2</em><em>3</em></h2>
<em>Sol</em><em>ution</em><em>,</em>
<em>Here</em><em>,</em><em> </em><em>n</em><em>=</em><em>5</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>x</em><em>></em><em>0</em>
<em>f</em><em>(</em><em>x</em><em>)</em><em>=</em><em>4</em><em>x</em><em>+</em><em>3</em>
<em> </em><em> </em><em> </em><em> </em><em>=</em><em>4</em><em>*</em><em>5</em><em>+</em><em>3</em>
<em> </em><em> </em><em> </em><em>=</em><em>2</em><em>0</em><em>+</em><em>3</em>
<em> </em><em> </em><em> </em><em>=</em><em>2</em><em>3</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>